在 iOS 中存储和执行大量操作

问题描述

我如何处理具有以下数字的操作:48534588306961133067968196965257961415756656521818848750723547477673457670019632882524164647651492025728980571833579341743986

到目前为止，我尝试过的任何方法都没有... unsigned long、long long 等...

解决方案

你可以改用 JKBigInteger，它是 LibTomMath C 库的 Objective-C 包装器.而且非常易于使用和理解.

在你的情况下:

  JKBigInteger * INT = [[JKBigInteger的alloc] initWithString:@ 48534588306961133067968196965257961415756656521818848750723547477673457670019632882524164647651492025728980571833579341743988603191694784406703"];

How could I handle operations with a number like:48534588306961133067968196965257961415756656521818848750723547477673457670019632882524164647651492025728980571833579341743988603191694784406703

Nothing that I've tried worked so far... unsigned long, long long, etc...

解决方案

You could use JKBigInteger instead, it is a Objective-C wrapper around LibTomMath C library. And really easy to use and understand.

In your case:

JKBigInteger *int = [[JKBigInteger alloc] initWithString:@"48534588306961133067968196965257961415756656521818848750723547477673457670019632882524164647651492025728980571833579341743988603191694784406703"];

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