问题描述
我不想扫描目录及其子目录中的所有文件。并将其路径放在数组中。像数组中目录中文件的路径将只是
I want not scan all the files in a directory and its sub-directory. And get their path in an array. Like path to the file in the directory in array will be just
而子目录中文件的路径将为
while the path to a file in sub-directory will be
我可以扫描单个目录,但是它没有任何区别的方式返回所有的文件和子目录。
I am able to scan single directory, but it returns all the files and sub-directories without any ways to differentiate.
if ($handle = opendir('fonts/')) {
/* This is the correct way to loop over the directory. */
while (false !== ($entry = readdir($handle))) {
echo "$entry<br/>";
}
closedir($handle);
}
什么是最好的方法来获取目录和子目录中的所有文件,目录及其路径?
What is the best way to get all the files in the directory and sub-directory with its path?
推荐答案
使用SPL中的DirectoryIterator可能是最好的方法:
Using the DirectoryIterator from SPL is probably the best way to do it:
$it = new RecursiveIteratorIterator(new RecursiveDirectoryIterator('.'));
foreach ($it as $file) echo $file."\n";
$ file
是一个 -object。它的__toString()方法将为您提供文件名,但还有其他几种方法也很有用!
$file
is an SPLFileInfo-object. Its __toString() method will give you the filename, but there are several other methods that are useful as well!
有关更多信息,请参阅:
For more information see: http://www.php.net/manual/en/class.recursivedirectoryiterator.php
这篇关于在目录和子目录中扫描文件,并使用php将其路径存储在数组中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!