如何自动打开应用程序，而无需用户在收到Android推送请求的情况下进行操作

问题描述

我正在尝试在收到推送通知时打开一个应用程序.

I am trying to open an app when a push notification is received.

代码:

public class GCMIntentService extends GCMBaseIntentService {

    public GCMIntentService() {
        super("GCMIntentService");
    }

    @Override
    protected void onMessage(Context context, Intent intent) {
        Intent dialogIntent = new Intent(this, MyActivity.class);
        dialogIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        startActivity(dialogIntent);
    }
}

这是我到目前为止所拥有的.但是我不知道什么是MyActivity.class.

This is what I have so far.But I cannot figure out what MyActivity.class is.

假设我要启动该应用程序，仅此而已.我不想在AndroidManifest.xml中添加其他活动.

Let's say I want to start the app and that's it. I do not want to add another activity to the AndroidManifest.xml.

我不能简单地将MainActivity.class用于Cordova吗?

Can't I simply use MainActivity.class for Cordova?

MyActivity.class到底是什么?

What exactly is MyActivity.class?

推荐答案

PackageManager.getLaunchIntentForPackage 可以帮助您找到输入活动.

PackageManager.getLaunchIntentForPackage can help you find the entry activity.

    Intent launchIntent = context.getPackageManager().getLaunchIntentForPackage(context.getPackageName());
    launchIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    startActivity(launchIntent);

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