Connect 4中的对角线赢钱支票

问题描述

我正在开发具有7x7场，水平和垂直检查的Connect 4游戏，但是我没有得到对角线检查的工作

I am developing a Connect 4 game with 7x7 fields, horizontal and vertical checks but I dont get diagonal checks works

只要其中一个标记不在最后一列，我就可以赢.

I can win as long as one of the tokens is not in the last column.

所有这些检查:

private static int getWinningInDiagonals() {

    // Top-Left -> Bottom-Right
    for (int column = 0; column < 7; column++) {
        int count = 0;
        for (int row = 0; row < 7; row++) {
            if (field[row][column] != 0 && field[row+1][column + row - 1] == field[row][column])
                count++;
            else
                count = 1;
            if (count >= 4) {
                return field[row][column];
            }
        }
    }
    // Top-Right -> Bottom-Left
    for (int column = 0; column < 7; column++) {
        int count = 0;
        for (int row = 0; row < 7; row++) {
            if (field[row][column] != 0 && field[row+1][column - row + 1] == field[row][column])
                count++;
            else
                count = 1;
            if (count >= 4) {
                return field[row][column];
            }
        }
    }
    return 0;
}

推荐答案

对于每次要同时右移和右移的人，您也只需要转到3、3，因为对角线不会再出现比没有它离开数组边界的情况更是如此.

For one you want to move down and right at the same time every time, you also only need to go to 3, 3 as a diagonal cannot occur any farther than that without it leaving the bounds of the array.

如果我正确地假设您的左上角是您的0,0，那么这应该适用于您的左上角到底部右角.从右上到左下是更改列和行循环以及更改偏移量的方法.

This should work for your top left to bottom rights if I'm right in assuming that your top left is your 0,0.Doing top right to bottom left is a matter of changing the column and row loops and changing how the offset works.

// Top-Left -> Bottom-Right
for (int column = 0; column < 4; column++) {
    for (int row = 0; row < 4; row++) {
        player = 0;
        if (field[row][column] != 0){
            player=field[row][column];
            offset = 1;
        }
        while (player != 0){
            if (field[row + offset][column + offset] == player){
                offset += 1;
            }else{
                player = 0;
            }
        }
        if(offset >= 4){
            return field[row][column];
        }
    }
}

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