问题描述
现在,我正在按以下方式实现pmf模型:
Now I am implementing the pmf model as below:
pmf_code = """
data {
int<lower=0> K; //number of factors
int<lower=0> N; //number of user
int<lower=0> M; //number of item
int<lower=0> D; //number of observation
int<lower=0> D_new; //number of pridictor
int<lower=0, upper=N> ii[D]; //item
int<lower=0, upper=M> jj[D]; //user
int<lower=0, upper=N> ii_new[D_new]; // item
int<lower=0, upper=N> jj_new[D_new]; // user
real<lower=0, upper=5> r[D]; //rating
real<lower=0, upper=5> r_new[D_new]; //pridict rating
}
parameters {
row_vector[K] i[M]; // item profile
row_vector[K] u[N]; // user profile
real<lower=0> alpha;
real<lower=0> alpha_i;
real<lower=0> alpha_u;
}
transformed parameters {
matrix[N,M] I; // indicator variable
I <- rep_matrix(0, N, M);
for (d in 1:D){
I[ii[d]][jj[d]] <- 1;
}
}
model {
for (d in 1:D){
r[d] ~ normal(u[jj[d]]' * i[ii[d]], 1/alpha);
}
for (n in 1: N){
u[n] ~ normal(0,(1/alpha_u) * I);
}
for (m in 1:M){
i[m] ~ normal(0,(1/alpha_i) * I);
}
}
generated_quantities{
for (d in 1:D_new){
r_new[d] <- normal(u[jj_new[d]]' * i[ii_new[d]], 1/alpha);
}
}
"""
但在以下代码行中出现了No matches for: real ~ normal(matrix, real)
错误:
but got an No matches for: real ~ normal(matrix, real)
error in this line of code:
for (d in 1:D){
r[d] ~ normal(u[jj[d]]' * i[ii[d]], 1/alpha);
}
但是jj[d]
应该是int
,表示user
的ID.并且u[int]
应该是row_vector
具有k
因子的i[ii[d]]
.它们的乘积应该是单个实际值,为什么斯坦说它是矩阵?
But the jj[d]
should be a int
, denoting the id of user
. And u[int]
should be a row_vector
has k
factors and so is i[ii[d]]
. The product of them should be a single real value, why stan said it was a matrix?
提前谢谢!
最初的问题已通过添加产品的sum
解决.但是现在又发生了另一个错误:
The initial problem has been solved by adding a sum
of the product. But now another error occurs:
No matches for:
row vector ~ normal(int, matrix)
for (n in 1: N){
u[n] ~ normal(0,(1/alpha_u) * I);
}
在pmf模型中,I
是单位矩阵.因此,(1/alpha_u) * I
的乘积也是一个矩阵.但是斯坦只接受向量或实值作为方差.我想知道如何将其转换为向量或单个值.谢谢.
In the pmf model, I
is unit matrix. So the product of (1/alpha_u) * I
is also a matrix. But stan just accept vector or real value as variance. I wonder how to transform it to a vector or a single value. Thanks.
推荐答案
Stan是一种静态类型的语言. vector
乘以row_vector
将得到matrix
.在这种情况下,它是一个1x1矩阵.有关operator*
的返回类型,请参见手册v2.9.0版的355页.
Stan is a statically typed language. A vector
multiplied by a row_vector
will result in a matrix
. In this case, it's a 1x1 matrix. For the return type of operator*
, see page 355 of the v2.9.0 version of the manual.
而不是相乘,而是使用dot_product()
.
Rather than multiplying, use dot_product()
instead.
这篇关于将两个1 * k向量相乘,但没有匹配:pystan中的real〜normal(matrix,real)错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!