问题描述
我有一个读取非结构化网格的代码.我围绕 sympy.geometry
的几何实体编写了包装器,例如:
I have a code which reads unstructured mesh. I wrote wrappers around geometric entities of sympy.geometry
such as:
class Point:
def __init__(self, x, y, parent_mesh):
self.shape = sympy.geometry.Point(x,y)
self.parent_mesh = parent_mesh
self.parent_cell = list()
一切正常,但 sympy.geometry.Point
的初始化对于每个 Point
需要花费大量时间.实际上,代码没有执行完数千个点.用 C++ 编写的类似代码在几秒钟内完成.没有它,代码足够快(我删除了它并计时).我读到一个可能的原因可能是 sympy.geometry
为了精度将浮点数转换为有理数.有没有办法(标志)来加速 sympy.geometry
因为我不需要精确的精度?
Everything works fine but initialization of sympy.geometry.Point
takes a lot of time for each Point
. Actually, the code did not finish execution for thousands of points. Similar code written in C++ finished in a few seconds. Without it the code is fast enough (I removed it and timed). I read that a possible reason could be that sympy.geometry
converts floating point numbers to rationals for precision. Is there a way (flag) to speed up sympy.geometry
as I do not need exact precision?
推荐答案
查看Point
类文档,特别是在第一个示例中:
Take a look at the Point
class documentation, specifically, in one of the first examples:
浮点数会自动转换为 Rational,除非评估标志为 False
.
因此,您可以在 Point
类的初始化过程中传递一个名为 evaluate
的标志:
So, you could pass a flag named evaluate
during initialization of your Point
classes:
self.shape = sympy.geometry.Point(x,y, evaluate=False)
这显然表明你在追求什么.
which apparently signals what you're after.
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