本文介绍了TypeError:列表索引必须是整数或切片,而不是浮点型的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

def convBin():
    cont = []
    rest = []
    dev = []
    decimal = []

    print("Ingrese el valor a convertir: ")
    valor = ast.literal_eval(input())

    if isinstance(valor, int):
        while valor > 0:
                z = valor // 2
            resto = valor%2
            valor = valor // 2
            cont.append(z)
            rest.append(resto)

        cont.reverse()
        rest.reverse()

        dev.append(cont[0])

        x = 0
        while x <= (len(rest) - 1):
            dev.append(rest[x])
            x += 1

        print(" ")
        print("Lista de devoluciones: ")
        print(dev)
        print("")

    elif isinstance(valor, float):
        a = valor // 1
        b = valor % 1

        while a > 0:
            z = a // 2
            resto = a%2
            a = a // 2
            cont.append(z)
            rest.append(resto)

        cont.reverse()
        rest.pop()

        dev.append(cont[1])

        for i in rest:
            dev.append(rest[i])

        print("Inserte el número de error minimo")
        num = input()

        while num > 0:
            dec = b * 1
            dec2 = dec//1
            dec %= 1
            decimal.append(dec2)


        print("Parte entera: ")
        print(dev)
        print("Parte decimal:")
        print(num)

    else:
        print("Ha aparecido un error")

它向我显示了一个错误,我无法将浮点数添加到列表中.

Its shows me an error that i can´t append a float into a list.

询问您的电话号码后,它可以控制电话号码的类型.如果它是整数,则没有任何问题.但是,当它是一个浮点数时,它表示不能将一个浮点数添加到保存以前执行的操作数的列表中.

After asking you a number, it controls which type of number is it. When it is an int, it doesn´t have any problem. But when it´s a float, it says that it can´t add a float into a list where it´s saved the numbers of the operations made before.

有人可以向我解释为什么我不能将浮点数添加到列表中或者如何解决该问题吗?

Can someone explain it to me why I can´t append floats into a list or how can I solve the problem?

谢谢.

推荐答案

我在休息的时候将为您提供列表中的实际项目,而不是索引.从您的代码看来,您似乎想附加该值.但是实际上,您将值再次视为索引,并尝试从数组中获取它.

for i in rest will give you the actual item in the list, and not index. From your code, it seems that you want to append the value. But actually, you are treating the value as index again, and trying to fetch it from the array.

for i in rest:
            dev.append(rest[i])

修复:

只需在上方更改为:

dev.extend(rest)

但是此代码从休息中获取一个值,然后再次将该值用作索引,如果该值 i 原来是 float ,它将抛出一个例外.

But this code, takes a value from rest, then again uses that value as an index, and if that value i turns out to be a float, it throws an exception.

您还没有提到哪一行会给您此错误.但是我认为一定是这个.它可能会带来许多其他意外错误,例如数组越界

You haven't mentioned which line gives you this error. But I think it must be this one. It might give many other unexpected errors like array out of bound, etc

如果我为valor = 18.5运行您的代码,这就是我得到的错误

This is the error I get, if I run your code for valor = 18.5

https://ideone.com/HGagLb

上面的示例与下面的示例之间的区别(从您的代码中,您在其中处理 int 的地方):

Difference between the above example, and the one below(from your code, where you handle int):

x = 0
while x <= (len(rest) - 1):
    dev.append(rest[x])
    x += 1

在第一种情况下,我实际上是列表其余部分中的项目(int或float),而在后一种情况下,它是有效索引.

is that, in the first case, i is actually the item(int or float) in the list rest, while in the later one, it's a valid index.

这篇关于TypeError:列表索引必须是整数或切片,而不是浮点型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-21 11:44