TypeError:列表索引必须是整数或切片，而不是列表

问题描述

array =一种具有3列的列表，其中包含数据的行数不受限制.

array = some kind of list with 3 columns and unlimited amount of rows with data inside of it.

Volume = array[0][2]
counter = 0
for i in array:
    if Volume == array[i][2]: #<------ why is this line a problem?
        counter += 1

推荐答案

这是一个经典的错误.在您的情况下，i已经是array(即另一个列表)中的元素， not 的索引是array( not 和int)，因此

This is a classic mistake. i in your case is already an element from array (i.e. another list), not an index of array (not an int), so

if Volume == i[2]:
    counter += 1

请确保至少经历 Python的开头教程，因为这是非常简单和基本的内容.

Please, make sure to go at least through the beginning of Python tutorial, because this is very simple and fundamental stuff.

我也建议您遵循命名约定:变量通常是小写字母(volume，而不是Volume).在这种情况下，i具有误导性. row或elem更合适.

Also I would advise to stick to naming conventions: variables are normally lower-case (volume, not Volume). In this case i is misleading. row or elem would be much more suitable.

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