和similarObject之间的区别

和similarObject之间的区别

本文介绍了&(* similarObject)和similarObject之间的区别?他们不一样吗?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

有人可以向我解释这个问题。

  dynamic_cast< SomeObject *>(&(* similarObject) 

执行取消引用指针的地址的意义是什么?

解决方案

这可能是 similarObject 已经重载运算符* ,因此它返回的东西的地址,你传递到 dynamic_cast



&(* x) x 可能不会总是相同的东西。例如,想到迭代器:

  std :: map< int,int> :: iterator it = v.begin ; 

然后 it 是两个不同的东西:




  • std :: map

  • &(* it) std :: pair< int,int> *
  • / ul>

    它们不是 。类似的事情也可能发生在你的代码片段。


    Can someone please explain this to me

    dynamic_cast<SomeObject *>( &(*similarObject) );
    

    What is the point of doing the address of a dereferenced pointer? Wouldn’t the pointer itself just be the address of it?

    解决方案

    It may be that the type of similarObject has overloaded operator* and so it returns something whose address you're passing to dynamic_cast.

    &(*x) and x may not be always the same thing. For example, think of iterator:

    std::map<int, int>::iterator it = v.begin();
    

    Then it and &(*it) are two different thing:

    • The type of it is std::map<int, int>::iterator
    • The type of &(*it) is std::pair<int,int>*

    They're not at all same. Similar thing may happen with your code-snippet as well.

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08-21 11:29