本文介绍了合并具有相同键值对的对象数组中的值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下数组:
const arr = [
{
id:"aaa",
name:"aaa",
type:"director",
nodes:[
{
type:"manager",
id:"111",
name:"111"
}
]
},
{
id:"aaa",
name:"bbb",
type:"director",
nodes:[
{
type:"manager",
id:"222",
name:"222"
}
]
},
{
id:"aaa",
name:"aaa",
type:"director",
nodes:[
{
type:"manager",
id:"333",
name:"333"
}
]
},
{
id:"aaa",
name:"bbb",
type:"director",
nodes:[
{
type:"manager",
id:"444",
name:"444"
}
]
}
]
所需的输出:
const arr = [
{
id:"aaa",
name:"aaa",
type:"director",
nodes:[
{
type:"manager",
id:"111",
name:"111"
},
{
type:"manager",
id:"333",
name:"333"
}
]
},
{
id:"aaa",
name:"bbb",
type:"director",
nodes:[
{
type:"manager",
id:"222",
name:"222"
},
{
type:"manager",
id:"444",
name:"444"
}
]
}
我正在尝试将上述数组中具有相同键值(id,名称和类型)对的节点对象数组的值合并到所需的输出中.
I am trying to merge the value of the array of objects of nodes that have the same key-value(id, name, and type) pairs in the above array to the desired output.
我尝试了以下方法,但与arr.reduce却是徒劳的,但徒劳的:
I have tried the following but in vain with the arr.reduce, but in vain:
arr.reduce((acc, el) => {
var existEl = acc.find(e => e.nodes.id === el.nodes.id);
if (existEl) {
existEl = el;
} else {
acc.push(el);
}
return acc;
}, []);
任何帮助将不胜感激.预先感谢.
Any help would be much appreciated. Thanks in advance.
推荐答案
您可以使用 Map
并收集具有相同id
和name
var array = [{ id: "aaa", name: "aaa", type: "director", nodes: [{ type: "manager", id: "111", name: "111" }] }, { id: "aaa", name: "bbb", type: "director", nodes: [{ type: "manager", id: "222", name: "222" }] }, { id: "aaa", name: "aaa", type: "director", nodes: [{ type: "manager", id: "333", name: "333" }] }, { id: "aaa", name: "bbb", type: "director", nodes: [{ type: "manager", id: "444", name: "444" }] }],
result = [...array.reduce((m, o) => {
var key = ['id', 'name'].map(k => o[k]).join('|');
if (m.has(key)) {
m.get(key).nodes.push(...o.nodes);
} else {
m.set(key, Object.assign({}, o, { nodes: o.nodes }));
}
return m;
}, new Map).values()];
console.log(result);
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