避免重复来自WorkManager的PeriodicWorkRequest | 自WorkManager的PeriodicWorkRequest

本文介绍了避免重复来自WorkManager的PeriodicWorkRequest的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

在启动应用程序时，我想启动将永远运行的服务，但是当用户再次打开应用程序时，它将重复.

On Application start I want to start service that will work forever, but when user opens app again it duplicates.

PeriodicWorkRequest.Builder sendDataBuilder = new PeriodicWorkRequest.Builder(SendConnectionMetricsWorker.class, Constants.REPEAT_TIME_INTERVAL_IN_HOURS, Constants.REPEAT_TIME_INTERVAL_UNITS)
                .setConstraints(new Constraints.Builder()
                        .setRequiredNetworkType(NetworkType.CONNECTED)
                        .build());
        PeriodicWorkRequest periodicWorkRequest = sendDataBuilder
                .build();
        WorkManager.getInstance().enqueue(periodicWorkRequest);

推荐答案

您可以使用 enqueueUniquePeriodicWork 代替 enqueue .根据文档:

You can use enqueueUniquePeriodicWork instead of enqueue. Based on the documentation:

您可以通过以下方式实现它:

You can achieve it as follows:

PeriodicWorkRequest.Builder sendDataBuilder = new PeriodicWorkRequest.Builder(SendConnectionMetricsWorker.class, Constants.REPEAT_TIME_INTERVAL_IN_HOURS, Constants.REPEAT_TIME_INTERVAL_UNITS)
                .setConstraints(new Constraints.Builder()
                        .setRequiredNetworkType(NetworkType.CONNECTED)
                        .build());
 PeriodicWorkRequest periodicWorkRequest = sendDataBuilder
                .build();
 WorkManager.getInstance().enqueueUniquePeriodicWork("Send Data",  ExistingPeriodicWorkPolicy.KEEP,periodicWorkRequest);

注意:

ExistingPeriodicWorkPolicy.REPLACE 确保如果存在标记为uniqueWorkName的待处理工作，它将被取消并运行新工作. ExistingPeriodicWorkPolicy.KEEP 仅在没有标记有uniqueWorkName的待处理工作时才运行新的PeriodicWorkRequest.

ExistingPeriodicWorkPolicy.REPLACE ensures that if there is pending work labelled with uniqueWorkName, it will be cancelled and the new work will run. ExistingPeriodicWorkPolicy.KEEP will run the new PeriodicWorkRequest only if there is no pending work labelled with uniqueWorkName.

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