抓住XPath中的同级兄弟? | 抓住XPath中的同级兄弟

本文介绍了抓住XPath中的同级兄弟?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我试图根据以下包含树中某个单词的树中较高位置的强标签来捕获 li 类文本:"restaurants":

I am trying to grab the li class text in the following based on the strong tag higher up in the tree containing a certain word, in this case: "restaurants":

<p class="">The location, where the condo is situated,
            offers a good choice of <strong>restaurants</strong>.
            Some of them are listed below:</p>
<ul class="">
<li class="">Restaurant 1</li>
<li class="">Restaurant 2</li>
<li class="">Restaurant 3</li>
<li class="">Restaurant 4</li>
<li class="">Restaurant 5</li>
</ul>

假设我需要使用祖先"在树上向上移动，我尝试了以下几种变体:

I have tried many variations of the following, assuming that I need to go higher up the tree by using "ancestors":

//ul/li[contains(ancestor-or-self::@strong[contains(text(),'Restaurants')])

推荐答案

此XPath，

//p[strong = 'restaurants']/following-sibling::ul[1]/li

将在包含 strong 的 p 元素的同级元素之后，选择第一个 ul 元素的所有 li 元素>字符串值为"restaurants" 的元素.

will select all li elements of the first ul element following sibling of the p element that contains a strong element whose string value is "restaurants".

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