问题描述
我将Excel中遇到的问题翻译为R.我想以"Gesamt"(由函数返回)最大化的形式分配固定的预算.
i translated a Problem I had in Excel into R. I want to allocate a fixed Budget in a form that "Gesamt" (which is returned by the function) is maximized.
NrwGes <- function(Budget, Speed, maxnrw, cpcrp) {
BudgetA <- Budget[1]
BudgetB <- Budget[2]
BudgetC <- Budget[3]
BudgetD <- Budget[4]
BudgetE <- Budget[5]
MaxNRW <- c(90, 40, 40, 25, 15)
Speed <- c(0.9, 0.9, 0.9, 0.9, 0.9)
cpcrp <- c(6564, 4494, 3962, 4525, 4900)
TV <- BudgetA*1000/cpcrp[1]
Catchup <- BudgetB*1000/cpcrp[2]
YT <- BudgetC*1000/cpcrp[3]
FB <- BudgetD*1000/cpcrp[4]
Display <- BudgetE*1000/cpcrp[5]
a <- TV^Speed[1]/(1+abs((TV)^Speed[1]-1)/(MaxNRW[1]*0.98))
b <- Catchup^Speed[2]/(1+abs((Catchup)^Speed[2]-1)/(MaxNRW[2]*0.98))
c <- YT^Speed[3]/(1+abs((YT)^Speed[3] -1)/(MaxNRW[3]*0.98))
d <- FB^Speed[4]/(1+abs((FB)^Speed[4]-1)/(MaxNRW[4]*0.98))
e <- Display^Speed[5]/(1+abs((Display)^Speed[5]-1)/(MaxNRW[5]*0.93))
Gesamt <- a+(100-a)/100*b+((100-a)/100*(100-b)/100*c)+((100-a)/100*(100-b)/100*(100-c)/100*d)+((100-a)/100*(100-b)/100*(100-c)/100*(100-d)/100*e)
return(Gesamt)
}
我有一个总预算(即5000),可以分配不同的预算以最大化"Gesamt".例子:
I have a total Budget (i.e 5000), which can be allocated differently to maximize "Gesamt". Examples:
NrwGes(c(5000, 0, 0, 0, 0)) # 72.16038
NrwGes(c(2000, 1500, 1000, 500, 0)) # 84.23121
不能使用强行强制"或网格搜索",因为它将执行15-20次,并且该算法将应用于R-Shiny应用程序.
Brute Forcing or grid search is not an option since this will be done 15-20 times and the algorithm will be applied to an R-Shiny App.
推荐答案
一个选项是nloptr
package:
An option is nloptr
package :
library(nloptr)
# we use NLOPT_LN_COBYLA algorithm because it doesn't need gradient functions
opts <- list(algorithm="NLOPT_LN_COBYLA",
xtol_rel=1.0e-8,
maxeval=10000)
# objective function (negative because nloptr always minimize)
objFun <- function(x){ -NrwGes(x) }
# sum of budget <= 5000 (in the form g(x) <= 0)
g <- function(x){ sum(x) - 5000 }
res <- nloptr(x0=rep.int(0,5), # initial solution (all zeros)
eval_f=objFun,
lb=rep.int(0,5), # lowerbounds = 0
ub=rep.int(5000,5), # upperbounds = 5000
eval_g_ineq=g,
opts=opts)
结果:
> res
Call:
nloptr(x0 = rep.int(0, 5), eval_f = objFun, lb = rep.int(0, 5),
ub = rep.int(5000, 5), eval_g_ineq = g, opts = opts)
Minimization using NLopt version 2.4.2
NLopt solver status: 4 ( NLOPT_XTOL_REACHED: Optimization stopped because xtol_rel
or xtol_abs (above) was reached. )
Number of Iterations....: 261
Termination conditions: xtol_rel: 1e-08 maxeval: 10000
Number of inequality constraints: 1
Number of equality constraints: 0
Optimal value of objective function: -86.6428477187536
Optimal value of controls: 3037.382 695.3725 675.7232 386.2929 205.2291
您可以使用res$solution
,res$objective
等访问解决方案,解决方案的目标.
N.B. you can access to solution, objective of res using res$solution
, res$objective
etc.
这篇关于R中预算分配的优化(以前是Excel Solver)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!