找到数字的总和，直到只剩下1位数

问题描述

大家好，



我在创建一个循环达到1位数时遇到了一些困难。例如，999992确实变为47和11，但不是2，因为它应该....



这是我的代码：

Hi guys,

I am having some difficulties creating a loop to get to 1 digit. E.g 999992 does change to 47 and 11, but not to 2 as it should....

Here's my code:

#include "stdafx.h"
#include <iostream>
using namespace std;

int main()
{
	int n, sum=0, total=0;
	cout << "Enter an integer." << endl;
	cin >> n;
	cout << "You have entered: " << n << endl;

	while (n > 0) {
	 sum += n % 10;
	 n /= 10;
	}

	cout << "The digitsum is: " << sum << endl;

	if (sum < 10)
	 cout << "The total digitsum is: "<< sum << endl;
	else
	 do {
	  total += sum % 10;
	  sum /= 10;
	  cout << "The total digitsum is: " << total << endl;
	 } while (total < 10);

	system("pause");
	return 0;
}

任何人都可以帮我吗？

Can anyone help me out here?

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