本文介绍了安卓:从文件中读取(Openfileinput)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我写了一个单元一个基本的记事本应用程序,在大学。我创建了主类与EDITTEXT我保存为字符串textOutput。

I am writing a basic notepad app for a unit at uni. I have created the main class with an editText which I save as string textOutput.

我已经使用的Andr​​oid开发者网站上的以下code字符串保存到一个文件中:

I have used the following code from the android developers website to save the string to a file:

            FileOutputStream fos = openFileOutput(textOutput, Context.MODE_PRIVATE);
            fos.write(textOutput.getBytes());
            fos.close();

不过,他们说看你使用了以下几个阶段:

However, they say to read you use the following stages:

要读取内部存储的文件:

呼叫openFileInput(),并通过读取文件的名字吧。这将返回一个FileInputStream。  阅读与从文件中读取的字节()。  然后关闭与关闭()流。

Call openFileInput() and pass it the name of the file to read. This returns a FileInputStream. Read bytes from the file with read(). Then close the stream with close().

这到底这是否意味着,谁给我落实到我的应用程序?

What the hell does this mean, and who to I implement it into my app?

请帮忙。

推荐答案

如何使用的一个例子的 openFileInput 的:

An example of how to use openFileInput:

    FileInputStream in = openFileInput("filename.txt");
    InputStreamReader inputStreamReader = new InputStreamReader(in);
    BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
    StringBuilder sb = new StringBuilder();
    String line;
    while ((line = bufferedReader.readLine()) != null) {
        sb.append(line);
    }

这篇关于安卓:从文件中读取(Openfileinput)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-21 06:38