由于java语言规则或jvm，是否将字节转换为int？

问题描述

byte a = 1;
byte b = 1;
byte c = a + b;

引发错误：可能会失去精确度

Throws error: possible loss of precision

byte subt = a_s - a_b;
                ^
  required: byte
  found:    int

这是行为与jvm或它在java语言中定义有关。

Is this behavior has something to do with jvm or its been defined in java language .

编辑：如果它是用java语言定义那么就做因为记住jvm？

EDIT : And if it is defined in java language then does it because of keeping jvm in mind ?

意味着如果java支持 byte datatype那么为什么操作on byte results int

Means if java supports byte datatype then why operation on byte results int

推荐答案

因为这就是Java虚拟机的设计方式。没有指令集对字节类型执行操作。相反， int 类型的指令集用于 boolean ， byte ， char ，短类型。

Because that's how the Java Virtual Machine is designed. There is no instruction set to perform operation on a byte type. Rather the instruction set for int type is used for the operation on boolean, byte, char, and short types.

来自：

背后的原因也在该部分中指明：

The reason behind this is also specified in that section:

有关所有内容的详细信息指令集可用于各种类型，您可以查看该部分中的表。

For the details on what all instruction sets are available for various types, you can go through the table in that section.

还有一个表指定实际类型到JVM计算类型的映射：

There is also a table specifying the mapping of actual type to the JVM computational type:

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