Python:当我们不需要重复的随机样本时如何使用随机样本

问题描述

我的代码

import random

MyList = [[1,2,3,4,5,6,7,8],[a,s,d,f,g,h,h],[q,w,e,r,t,y]]
MyListRandom = []
random_number = 5
i=0
while True:
     random_list = randint(0,len(MyList))
     element_random = random.sample(MyList[random_list], 1)
     if element_random[0] not in MyListRandom:
     i = i+1
     MyListRandom.append(element_random[0])
else:
    continue
if(i>=random_number):
    break

如果我不想使用此代码进行检查

if I don't want to use this code to check it

 if element_random[0] not in MyListRandom:
     MyListRandom.append(element_random[0])

如果我不希望重复样本，还有其他更好的方法吗?

Is there a better way more than this if i don't want a duplicates sample?

推荐答案

来自文档 random.sample(MyList)将为您提供列表项中的唯一答案.对于您要从中采样的MyList中的重复项，只需将其设置为 set .

From the documentation random.sample(MyList) will give you unique answers from the list's items already. For duplicates in MyList you sample from, you can just make it a set.

此外，您不需要每个样本都循环，您只需为其指定一个k参数，它将返回k个许多随机样本.所以整个代码可以写成:

Also you don't need the loop for every sample, you can just give it a k argument and it will return k many random samples. So the whole code can be written as:

# I have flatten the whole list into one list
element_random = random.sample(set([item for sublist in MyList for item in sublist]), 5)

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