本文介绍了使用HSL亮度系数从SKColor返回较浅的颜色的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个iOS SKColor,我想将其转换为更浅的阴影(不透明,不透明/不透明),因此我想使用HSL亮度实现一个函数,该函数返回一个SKColor. IE.在函数内部,将原始SKColor转换为等效的HSL,然后对HSL亮度应用一个值以获得较浅的色度,然后将此HSL颜色转换回我可以使用的SKColor.
I have an iOS SKColor, that I want to convert to a lighter shade (that is opaque with no opacity/no transparency), therefore I would like to implement a function using the HSL lightness, that returns an SKColor. ie. inside the function, convert the original SKColor to the HSL equivalent, then apply a value to the HSL lightness to get a lighter color shade, then convert this HSL color back to an SKColor that I can use.
推荐答案
Xcode 8.2.1•Swift 3.0.2
Xcode 8.2.1 • Swift 3.0.2
extension UIColor {
convenience init(hue: CGFloat, saturation: CGFloat, lightness: CGFloat, alpha: CGFloat = 1) {
let offset = saturation * (lightness < 0.5 ? lightness : 1 - lightness)
let brightness = lightness + offset
let saturation = lightness > 0 ? 2 * offset / brightness : 0
self.init(hue: hue, saturation: saturation, brightness: brightness, alpha: alpha)
}
var lighter: UIColor? {
return applying(lightness: 1.25)
}
func applying(lightness value: CGFloat) -> UIColor? {
guard let hsl = hsl else { return nil }
return UIColor(hue: hsl.hue, saturation: hsl.saturation, lightness: hsl.lightness * value, alpha: hsl.alpha)
}
var hsl: (hue: CGFloat, saturation: CGFloat, lightness: CGFloat, alpha: CGFloat)? {
var red: CGFloat = 0, green: CGFloat = 0, blue: CGFloat = 0, alpha: CGFloat = 0, hue: CGFloat = 0
guard
getRed(&red, green: &green, blue: &blue, alpha: &alpha),
getHue(&hue, saturation: nil, brightness: nil, alpha: nil)
else { return nil }
let upper = max(red, green, blue)
let lower = min(red, green, blue)
let range = upper - lower
let lightness = (upper + lower) / 2
let saturation = range == 0 ? 0 : range / (lightness < 0.5 ? lightness * 2 : 2 - lightness * 2)
return (hue, saturation, lightness, alpha)
}
}
let purple = UIColor(red: 160/255, green: 118/255, blue: 200/255, alpha: 1)
let lighter = purple.lighter
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