问题描述
我一直在玩Python和我有这个名单，我需要制定。基本上我的游戏类型列表到多维数组，然后每个人，它会基于第一个条目使3个变量。
I've been playing with Python and I have this list that I need worked out. Basically I type a list of games into the multidimensional array and then for each one, it will make 3 variables based on that first entry.
阵列即发：
Applist = [
['Apple', 'red', 'circle'],
['Banana', 'yellow', 'abnormal'],
['Pear', 'green', 'abnormal']
]
有关循环，每个水果指定名称，颜色和形状。
For loop to assign each fruit a name, colour and shape.
for i in Applist:
i[0] + "_n" = i[0]
i[0] + "_c" = i[1]
i[0] + "_s" = i[2]
在这样做，虽然，我得到一个不能分配给操作员消息。我该如何应对呢？
When doing this though, I get a cannot assign to operator message. How do I combat this?
预期的结果将是：
Apple_n == "Apple"
Apple_c == "red"
Apple_s == "circle"
等，为每个水果。
Etc for each fruit.
推荐答案
这是一个坏主意。你不应该动态地创建变量名，使用字典来代替：
This is a bad idea. You should not dynamically create variable names, use a dictionary instead:
variables = {}
for name, colour, shape in Applist:
variables[name + "_n"] = name
variables[name + "_c"] = colour
variables[name + "_s"] = shape
现在访问它们为变量[Apple_n] 等
你真正想要什么，虽然，也许是类型的字典的字典：
What you really want though, is perhaps a dict of dicts:
variables = {}
for name, colour, shape in Applist:
variables[name] = {"name": name, "colour": colour, "shape": shape}
print "Apple shape: " + variables["Apple"]["shape"]
或者，也许甚至更好，一<$c$c>namedtuple:
from collections import namedtuple
variables = {}
Fruit = namedtuple("Fruit", ["name", "colour", "shape"])
for args in Applist:
fruit = Fruit(*args)
variables[fruit.name] = fruit
print "Apple shape: " + variables["Apple"].shape
您不能改变每个变量水果如果你使用了 namedtuple 虽然（即没有设置变量[苹果。颜色到绿色），所以它也许不是一个好的解决方案，这取决于预期的用法。如果你喜欢 namedtuple 解决方案，但想改变的变量，你可以把它一个完全成熟的水果类，而不是，它可以用作上述code一个下拉更换为 namedtuple 水果。
You can't change the variables of each Fruit if you use a namedtuple though (i.e. no setting variables["Apple"].colour to "green"), so it is perhaps not a good solution, depending on the intended usage. If you like the namedtuple solution but want to change the variables, you can make it a full-blown Fruit class instead, which can be used as a drop-in replacement for the namedtuple Fruit in the above code.
class Fruit(object):
def __init__(self, name, colour, shape):
self.name = name
self.colour = colour
self.shape = shape
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