本文介绍了动态生成多个d3 svg图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个名为graphData的对象数组(大小各不相同).每个元素都包含创建d3图所需的所有信息,如果我通过硬编码(即graphdata[0]graphdata[1]等)访问graphData元素,则能够成功绘制这些图.

I've got an array of objects called graphData (size varies). Each element contains all the information required to create a d3 graph, and I am able to successfully draw the graphs if I access graphData elements by hardcoding (i.e. graphdata[0], graphdata[1] etc).

当我尝试使用for循环为每个元素生成一个图形时,问题就来了.环顾了stackoverflow和网络,但是解决方案都是关于生成固定数量的多个图,而不是动态生成多个图.

The problem comes when I attempt to use a for loop to generate one graph for each of the elements. Looked around stackoverflow and the web, but the solutions are all about generating a fixed number of multiple graphs, not generating multiple graphs dynamically.

下面是我的用于生成一个图形的工作代码.自动生成x个图形的推荐方法是什么?

Below is my working code for generating one graph. What is the recommended way to generate x number of graphs automatically?

   var graphData = data.graph;

    var RADIUS = 15;

    var edgeData = graphData[0].edges;
    var nodeData = graphData[0].nodes;
    var stageNum = graphData[0].stage;


    var xScale = d3.scale.linear()
        .domain([d3.min(edgeData, function (d) {
            return d.start[0];
        }),
            d3.max(edgeData, function (d) {
                return d.start[0];
            })])
        .range([50, w - 100]);

    var yScale = d3.scale.linear()
        .domain([d3.min(edgeData, function (d) {
            return d.start[1];
        }),
            d3.max(edgeData, function (d) {
                return d.start[1];
            })])
        .range([50, h - 100]);

    var rScale = d3.scale.linear()
        .domain([0, d3.max(edgeData, function (d) {
            return d.start[1];
        })])
        .range([14, 17]);

    // already have divs with classes stage1, stage2... created.
    var svg = d3.select(".stage" + stageNum).append("svg")
        .attr({"width": w, "height": h})
        .style("border", "1px solid black");

    var elemEdge = svg.selectAll("line")
        .data(edgeData)
        .enter();

    var edges = elemEdge.append("line")
        .attr("x1", function (d) {
            return xScale(d.start[0]);
        })
        .attr("y1", function (d) {
            return yScale(d.start[1]);
        })
        .attr("x2", function (d) {
            return xScale(d.end[0]);
        })
        .attr("y2", function (d) {
            return yScale(d.end[1]);
        })
        .attr("stroke-width", 2)
        .attr("stroke", "black");


    var elemNode = svg.selectAll("circle")
        .data(nodeData)
        .enter();

    var nodes = elemNode.append("circle")
        .attr("cx", function (d) {
            return xScale(parseInt(d.x));
        })
        .attr("cy", function (d) {
            return yScale(parseInt(d.y));
        })
        .attr({"r": rScale(RADIUS)})
        .style("fill", "yellow")
        .style("stroke", "black");

推荐答案

Mike Bostock建议将图表实现为可重用使用方法关闭.如果您愿意,这将是您的理想选择

Mike Bostock recommends implementing charts as reusable closures with methods. This would be an ideal implementation in your case as you want to have

  • 具有不同数据的多个图
  • 可能会重新加载新数据(希望这是动态的意思吗?)

粗略地讲,您想要做的就是将上面的代码包装到一个函数中,就像Mike在上面的帖子中描述的一样,然后将data作为关闭的属性.因此,这是一些严重被黑的代码:

In broad strokes, what you want to do is wrap your code above into a function in very much the same way Mike describes in the post above, and then have data be an attribute of your closure. So here is some badly hacked code:

// your implementation here
var chart = function(){...}

var graphData = d3.json('my/graphdata.json', function(error, data){
  // now you have your data
});

// let's say you have a div called graphs
var myGraphs = d3.select('.graphs')
  .data(graphData)
  .enter()
  .append('g')
  //now you have g elements for each of your datums in the graphData array

//we use the saved selection above and call the chart function on each of the elements in the selection
myGraphs.call(chart);

//note that internally in your `chart` closure, you have to take in a selection
//object and process it(data is already bound to each of your selections from above):
function chart(selection) {
    selection.each(function(data) {
//...

这里还有更多有关该主题的好读物.

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08-21 05:41