问题描述
我在这个主题上看到了很多话题,但没有一个答案.实际上是否有一个JAVA库可以使用XSD架构进行XML => JSON => XML的转换,从而更好地处理XML中单个元素的问题.
I saw lots of threads on this topic but not one with an answer.Is there actually a JAVA library which can make a conversion XML => JSON => XML using an XSD Schema to better handle the problematic of single element in XML.
(XML中的单个元素可以是数组或单个对象,具体取决于XSD架构)
(a single element in XML can be an array or a single object depending of the XSD schema)
XML示例:
<root><person><name>test</name></person></root>
JSON可以是:
{"root": [{"person": [{"name": "test"}]}]}
或带有对象而不是数组的任何东西:
or anything with object instead of array :
{"root": {"person": {"name": "test"}}}
但是使用XSD,我们可以从maxoccurs参数中知道root是唯一的,person是一个数组,而name是唯一的,因此良好的转换应该是:
But with XSD we would know from the maxoccurs parameters that root is unique, person is an array and name is unique, so the good transformation would be :
{"root": {"person":
[{"name": "foofdo"}]
}}
提前谢谢
推荐答案
如果您使用的是 Java 8 或更高版本,则应签出我的开源库: unXml . unXml基本上是从Xpaths映射到Json属性.
If you are using Java 8 or later, you should check out my open source library: unXml. unXml basically maps from Xpaths to Json-attributes.
可以在 Maven Central 中使用.
示例
import com.fasterxml.jackson.databind.node.ObjectNode;
import com.nerdforge.unxml.factory.ParsingFactory;
import com.nerdforge.unxml.parsers.Parser;
import org.w3c.dom.Document;
public class Parser {
public ObjectNode parseXml(String xml){
Parsing parsing = ParsingFactory.getInstance().create();
Document document = parsing.xml().document(xml);
Parser<ObjectNode> parser = parsing.obj("/root/person")
.attribute("name")
.build();
ObjectNode result = parser.apply(document);
return result;
}
}
它将返回 Jackson ObjectNode
,并带有以下json:
It will return a Jackson ObjectNode
, with the following json:
{"name":"test"}
数组示例
或者,如果您有多个person
,则可以让它返回 Jackson ArrayNode
Alternativly if you have multiple person
, you can have it return a Jackson ArrayNode
import com.fasterxml.jackson.databind.node.ArrayNode;
import com.nerdforge.unxml.factory.ParsingFactory;
import com.nerdforge.unxml.parsers.Parser;
import org.w3c.dom.Document;
public class Parser {
public ArrayNode parseXml(String xml){
Parsing parsing = ParsingFactory.getInstance().create();
Document document = parsing.xml().document(xml);
Parser<ArrayNode> parser = parsing.arr("/root/person")
.attribute("name")
.build();
ArrayNode result = parser.apply(document);
return result;
}
}
这将为您的输入创建以下json:
This will create the following json for your input:
[{"name":"test"}]
这篇关于转换XML => JSON =>基于XSD架构的XML的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!