本文介绍了org.hibernate.exception.SQLGrammarException:无法获取增量生成器的初始值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用hibernate来编写简单的jsp注册表格,我正在遵循Exception
Hi i am trying to make simple jsp registration form using hibernate where i am getting following Exception
type Exception report
messageInternal Server Error
descriptionThe server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: org.hibernate.exception.SQLGrammarException: could not fetch initial value for increment generator
root cause
org.hibernate.exception.SQLGrammarException: could not fetch initial value for increment generator
root cause
com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'index) from user_registration' at line 1
这是我的
Userregistration.hbm.xml
<?xml version='1.0'?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Nov 9, 2011 6:53:58 PM by Hibernate Tools 3.2.1.GA -->
<hibernate-mapping>
<class name="com.hibernateClass.UserRegistration" table="user_registration">
<id name="index">
<generator class="increment"></generator>
</id>
<property name="userName"></property>
<property name="password"></property>
<property name="email"></property>
</class>
</hibernate-mapping>
hibernate.cfg.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<!-- Generated by MyEclipse Hibernate Tools. -->
<hibernate-configuration>
<session-factory>
<property name="hbm2ddl.auto">update</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="connection.url">jdbc:mysql://localhost:3306/employee</property>
<property name="connection.username">root</property>
<property name="connection.password"></property>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="show_sql">true</property>
<mapping resource="com/hibernateClass/UserRegistration.hbm.xml"/>
</session-factory>
</hibernate-configuration>
UserRegistration.java
public class UserRegistration implements java.io.Serializable {
int index;
String userName;
String password;
String email;
public int getIndex() {
return index;
}
public void setIndex(int index) {
this.index = index;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
}
我如何处理此异常得到我想要的输出
How can i handle this Exceptionand get my desired output
预先感谢
推荐答案
也许'index'是关键字.在sql编程中要小心,有些单词看起来像关键字,应该避免使用它们
maybe 'index' is a keyword .be careful in sql programming , some words look likes keywords ,you should avoid them
这篇关于org.hibernate.exception.SQLGrammarException:无法获取增量生成器的初始值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!