问题描述
我有两个要循环的数组.我正确地构造了它们,在进入for循环之前,我确实回显了它们以确保一切都可以.但是当我运行脚本时,它会输出错误:
I have two arrays that I want to loop in. I construct those properly and before going into for loop, I do echo them to be sure everything is ok with arrays.But when I run the script, it outputs an error:
l<=: syntax error: operand expected (error token is "<="
我咨询了强大的Google,并了解它缺少第二个变量,但是我之前提到过,我确实回显了这些值,并且一切似乎都还可以.这是代码段..
I consulted the mighty Google and I understood it suffers from the lack of the second variable, but I mentioned earlier I do echo the values and everything seems to be OK. Here is the snippet..
#!/bin/bash
k=0
#this loop is just for being sure array is loaded
while [[ $k -le ${#hitEnd[@]} ]]
do
echo "hitEnd is: ${hitEnd[k]} and hitStart is: ${hitStart[k]}"
# here outputs the values correct
k=$((k+1))
done
k=0
for ((l=${hitStart[k]};l<=${hitEnd[k]};l++)) ; do //this is error line..
let array[l]++
k=$((k+1))
done
for循环中的变量已正确回显,但for循环将无法工作..我在哪里错了?
The variables in the for loop are echoed correctly but for loop won't work.. where am I wrong?
gniourf_gniourf回答:
as gniourf_gniourf answered:
表示错误输出不是在循环开始时显示,而是在k的值大于数组索引的值时,指向数组不包含的索引...
meaning error output is displayed not at the beginning of the loop, but when k has a greater value than array's indices, pointing an index that array does not include...
推荐答案
那是因为在某些时候${hitEnd[k]}
扩展为空(未定义).我在((l<=))
上遇到了相同的错误.您应该将for
循环写为:
That's because at some point ${hitEnd[k]}
expands to nothing (it is undefined). I get the same error with ((l<=))
. You should write your for
loop as:
k=0
for ((l=${hitStart[0]};k<${#hitEnd[@]} && l<=${hitEnd[k]};l++)); do
,以便始终具有与数组${hitEnd[@]}
中定义的字段相对应的索引k
.
so as to always have an index k
that corresponds to a defined field in the array ${hitEnd[@]}
.
也可以代替
k=$((k+1))
你可以写
((++k))
完成!
您的脚本使用了更好的现代bash练习进行了修订:
Your script revised using better modern bash practice:
#!/bin/bash
k=0
#this loop is just for being sure array is loaded
while ((k<=${#hitEnd[@]})); do
echo "hitEnd is: ${hitEnd[k]} and hitStart is: ${hitStart[k]}"
# here outputs the values correct
((++k))
done
k=0
for ((l=hitStart[0];k<${#hitEnd[@]} && l<=hitEnd[k];++l)); do
((++array[l]))
((++k))
done
现在,我不太确定for
循环是否确实可以实现您想要的功能……您不是这个意思吗?
Now, I'm not too sure the for
loop does exactly what you want it to... Don't you mean this instead?
#!/bin/bash
# define arrays hitStart[@] and hitEnd[@]...
# define array array[@]
#this loop is just for being sure array is loaded
for ((k=0;k<${#hitEnd[@]};++k)); do
echo "hitEnd is: ${hitEnd[k]} and hitStart is: ${hitStart[k]}"
# here outputs the values correct
((++k))
done
for ((k=0;k<${#hitEnd[@]};++k)); do
for ((l=hitStart[k];l<=hitEnd[k];++l)); do
((++array[l]))
done
done
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