如何通过并获得数组作为参数传递给shell脚本

问题描述

我传递多个参数的shell脚本。
我该脚本我想创建第二个参数，直到最后一个参数数组。
这我能够与下面的事 -

I am passing multiple argument to a shell script.I that script I want to create an array from 2nd argument till the last argument.This I am able to do with below -

arg=$1
shift
while [[ $1 != '' ]]
do
        emailID[${#emailID[@]}]=$1
shift
done

这EMAILID阵列我想传递给第二个脚本的第二个参数，我想找回这第二个脚本的阵列。
有没有办法做到这一点在KSH / bash中？

This emailID array I want to pass to second script as second argument and I want to retrieve the array in this second script.Is there a way to do it in ksh/bash?

推荐答案

只需使用 $ {@：2} 。据介绍完美。

Just use ${@:2}. It is explained here perfectly.

和将它传递到另一个脚本：

And to pass it into another script:

./anotherScript "${@:2}"

当然，它不会把它作为数组（因为你不能传递一个数组），但它会传递数组作为单个参数的所有元素。

Of course it will not pass it as array (because you cannot pass an array), but it will pass all elements of that array as individual parameters.

好吧，让我们尝试这种方式。这是你的第一个脚本：

Okay, lets try it this way. Here is your first script:

#!/bin/bash
echo "Here is my awesome first argument: $1"
var=$1 # I can assign it into a variable if I want to!
echo 'Okay, and here are my other parameters!'
for curArg in "${@:2}"; do
    echo "Some arg: $curArg"
done
myArr=("${@:2}") # I can assign it into a variable as well!

echo 'Now lets pass them into another script!'
./anotherScript 'Wheeee' "${@:2}"

这是你的另一个脚本：

And here is your another script:

#!/bin/bash
echo 'Alright! Here we can retrieve some arguments!'
echo "Here we go: $@" # that is including 'Wheeee' from the previous script. But we can use the same trick from above if we want to.

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