本文介绍了在Java中将XML读取为字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有人可以帮我解决这个问题。我想知道如何将此示例作为字符串阅读?我知道如何阅读第一个,但不知道如何阅读它们
Could somebody help me with this. I would like to know how to read this example as string? I know how to read first one but don't know how to read them all
<Tr rn=\"000000000000000\" vr=\"T\" sSpre=\"S\" reg=\"P\" dSpre=\"2000-01-01\" dOdprt=\"2000-01-01\" iban=\"SI00\" eno=\"R\" vir=\"B\" maticnaPps=\"0000000000\"><Imetnik davcna=\"00000000\" matSub=\"0000000000\" drz=\"705\"><PopolnoIme>UNKNOWN</PopolnoIme><KratkoIme>UNKNOWN</KratkoIme><Naslov sifTipNaslova=\"00\" sifObcina=\"000\" sifPosta=\"0000\" sifUlica=\"0000\" sifNaselje=\"000\" stHisna=\"000\" sifHsmid=\"00000000\"><Obcina>UNKNOWN</Obcina><Posta>UNKNOWN</Posta><Ulica>UNKNOWN</Ulica><Naselje>UNKNOWN</Naselje></Naslov></Imetnik></Tr>
推荐答案
也许这就是你要找的?示例:
Maybe this is what you are looking for? Example here: http://ideone.com/N4jIO
import java.io.ByteArrayInputStream;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class Main {
public static void main(String... args) throws IOException, SAXException, ParserConfigurationException {
String xml = "<Tr rn=\"000000000000000\" vr=\"T\" sSpre=\"S\" reg=\"P\" dSpre=\"2000-01-01\" dOdprt=\"2000-01-01\" iban=\"SI00\" eno=\"R\" vir=\"B\" maticnaPps=\"0000000000\"><Imetnik davcna=\"00000000\" matSub=\"0000000000\" drz=\"705\"><PopolnoIme>UNKNOWN</PopolnoIme><KratkoIme>UNKNOWN</KratkoIme><Naslov sifTipNaslova=\"00\" sifObcina=\"000\" sifPosta=\"0000\" sifUlica=\"0000\" sifNaselje=\"000\" stHisna=\"000\" sifHsmid=\"00000000\"><Obcina>UNKNOWN</Obcina><Posta>UNKNOWN</Posta><Ulica>UNKNOWN</Ulica><Naselje>UNKNOWN</Naselje></Naslov></Imetnik></Tr>";
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new ByteArrayInputStream(xml.getBytes("UTF-8")));
print(doc.getDocumentElement(), "");
}
private static void print(Node e, String tab) {
if (e.getNodeType() == Node.TEXT_NODE) {
System.out.println(tab + e.getNodeValue());
return;
}
System.out.print(tab + e.getNodeName());
NamedNodeMap as = e.getAttributes();
if (as != null && as.getLength() > 0) {
System.out.print(" attributes=[");
for (int i = 0; i < as.getLength(); i++)
System.out.print((i == 0 ? "" : ", ") + as.item(i));
System.out.print("]");
}
System.out.println();
if (e.getNodeValue() != null)
System.out.println(tab + " " + e.getNodeValue());
NodeList childs = e.getChildNodes();
for (int i = 0; i < childs.getLength(); i++)
print(childs.item(i), tab + " ");
}
}
这篇关于在Java中将XML读取为字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!