问题描述
我有一个字符串:
String stringProfile = "0,4.28 10,4.93 20,3.75";
我试图把它变成一个如下数组:
I am trying to turn it into an array like as follows:
double [][] values = {{0, 4.28}, {10, 4.93}, {20, 3.75}};
我已经格式化了字符串以删除任何空格并用逗号替换:
I've formatted the string to remove any whitespace and replace with a comma:
String stringProfileFormatted = stringProfile.replaceAll(" ", ",");
所以现在String stringProfileFormatted =0,4.28,10,4.93,20 ,3.75;
So now String stringProfileFormatted = "0,4.28,10,4.93,20,3.75";
然后创建一个String数组:
I then create a String array:
String[] array = stringProfileFormatted.split("(?<!\\G\\d+),");
因此,对于数组中的每个元素,每2个逗号值为字符串。
So for every element in the Array is every 2 commas worth of string.
不知道如何转换成2d数组。这甚至是正确的方法吗?
Not sure how to then convert into a 2d array. Is this even the right way to go about it?
推荐答案
我会一步一步地解决这个问题。
I would go step by step resolving this task.
首先,我将原始 String
拆分为空格,
然后用逗号分割结果,然后创建一个 double
的数组,其中包含 Double.parseDouble(String value)
。
First, I would split the original String
by a space,then split the results by comma each and afterwards create an array of double
out of those values with Double.parseDouble(String value)
.
public static void main(String[] args) {
String stringProfile = "0,4.28 10,4.93 20,3.75";
// split it once by space
String[] parts = stringProfile.split(" ");
// create some result array with the amount of double pairs as its dimension
double[][] results = new double[parts.length][];
// iterate over the result of the first splitting
for (int i = 0; i < parts.length; i++) {
// split each one again, this time by comma
String[] values = parts[i].split(",");
// create two doubles out of the single Strings
double a = Double.parseDouble(values[0]);
double b = Double.parseDouble(values[1]);
// add them to an array
double[] value = {a, b};
// add the array to the array of arrays
results[i] = value;
}
// then print the result
for (double[] pair : results) {
System.out.println(String.format("%.0f and %.2f", pair[0], pair[1]));
}
}
是的,这些是很多行代码,但很可能比lambda表达式更容易理解(在我看来,它更酷,更优雅)。
Yes, these are a lot of lines of code, but most likely more easily understandable than lambda expressions (which are cooler and more elegant in my opinion).
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