如何将辅助参数传递给WorkManager类

问题描述

在我的一个带有Kotlin的android应用程序中，我想将WorkManager类用作通用类.这是我的班级，我希望通过传递预期的参数将其用作泛型:

In one of my android(with Kotlin) app I want to use WorkManager class as a generic one.This is my class where I want to use it as generic by passing expected params:

class CommonWorkManager<P, R> (appContext: Context, workerParams: WorkerParameters) : Worker(appContext, workerParams)
{
    var lambdaFunction: ((P) -> R)? = null

    override fun doWork(): Result {
        lambdaFunction
        return Result.SUCCESS
    }
}

这是我尝试创建此类的实例的方法:

This is how I am trying to create an instance of this class:

CommonWorkManager<Unit, Unit>(context!!, ).lambdaFunction= {
    presenter?.fetchMasterData()
}

那么我如何将workerParams作为第二个参数传递.

So How can I pass workerParams as a second param.

在CommonWorkManager<P, R>

推荐答案

似乎我们无法创建WorkerParameters的实例，因为它具有带注释@RestrictTo(RestrictTo.Scope.LIBRARY_GROUP)的隐藏构造函数.根据文档，我们不会创建Worker子类，图书馆为我们做到了:

It seems we can't create instances of WorkerParameters because it has hidden constructor with annotation @RestrictTo(RestrictTo.Scope.LIBRARY_GROUP).According to the documentation we don't create instances of Worker subclass, the library does it for us:

val work = OneTimeWorkRequest.Builder(CommonWorkManager::class.java).build()
WorkManager.getInstance().enqueue(work)

我们可以得出结论，我们无法创建通用的Worker，即您的情况下的CommonWorkManager<P, R>. WorkManager用于特定任务.

We can conclude that we can't create universal Worker, i.e. CommonWorkManager<P, R> in your case. WorkManager is intended for the specific tasks.

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