本文介绍了使用rr屈服到一个块的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用rr测试以下代码:

I'm trying to test the following code using rr:

response = RestClient.get(url, {:params => params}){|response, request, result| response }

在香草rspec中,您将执行以下操作:

In vanilla rspec, you would do something like this:

RestClient.should_receive(:get).with(url, {:params => params}).and_yield(response, request, result)

我如何对rr做同样的事情?

How would I do the same with rr?

设置:

let(:url) { "http://localhost/" }
let(:params) { {:item_id => 1234, :n => 5} }
let(:response) { Object.new }
let(:request) { Object.new }
let(:result) { Object.new }

我在以下方面尝试了多种变体:

I've tried a bunch of variations on:

mock(RestClient).get(url, {:params => params}) { response, request, result }

mock(RestClient).get(url, {:params => params}, &proc/lambda{}).return(result)

mock(RestClient).get(url, {:params => params}).yields(response, request, result)

mock(RestClient).get(url, {:params => params}).returns do |proc_as_block|
  response
end

但它们都不起作用.

推荐答案

最后得到了它.该请求请求帮助: https://github.com/btakita/rr/pull/82

Finally got it. This pull request helped: https://github.com/btakita/rr/pull/82

mock(RestClient).get(url, {:params => params}).yields(response, request, result) { response }

这篇关于使用rr屈服到一个块的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-28 12:10