普通防爆pression更换用空格非字母字符

普通防爆pression更换用空格非字母字符

本文介绍了普通防爆pression更换用空格非字母字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在试图建立一个正规的前pression但一直没能得到一个特定的条件下工作。

I have been trying to build a regular expression but haven't been able to get one specific condition to work.

我希望有一个正则表达式删除所有非字母字符,除破折号( - )。破折号应该只有当他们都用空格pfixed $ P $所取代。

I want a regex to remove all non alpha characters with the exception of dash (-). Dashes should only be replaced if they are prefixed by a space.

TEST-TEST -TEST#TEST.TEST

应改为

TEST-TEST TEST TEST TEST

我一直在使用 [^ A-ZA-Z0-9] 但一直没能包括一个或条件初始化。

I had been using [^a-zA-Z0-9] but haven't been able to include one OR condition init.

推荐答案

下面是我想出了(\ S-| [^ A-ZA-Z0-9 - ]) ...这将删除所有非字母数字,但保留 - 除非有收到了空间 -

Here is what I came up with (\s-|[^A-Za-z0-9-])... It will remove all non alphanumerics but keep the "-" except if there is a space before it " -"

测试使用sed在Linux中,此刻我没有访问VS或单声道,以测试在C#

Test using sed in Linux, at the moment I don't have access to VS or Mono to test in C#

echo "TEST-TEST -TEST#TEST.TEST -1234" | sed 's/\(\s-\|[^A-Za-z0-9-]\)/ /g'

输出

TEST-TEST TEST TEST TEST 1234

  • ()和|用于OR条件
  • 使用 \ S -
  • 我们首先删除所有 -
  • 接下来我们把所有字母数字和 - 与 [^ A-ZA-Z0-9 - ]
    • () and | are used for the OR condition
    • We first remove all " -" using \s-
    • next we keep all alphanumerics and "-" with [^A-Za-z0-9-]
    • 这篇关于普通防爆pression更换用空格非字母字符的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-20 17:13