问题描述
我正在使用 Spring 提供的这个很酷的东西:Spring RESTWebService(spring 的版本是 3).如果我从浏览器访问 URL,我可以看到 JSON 响应,但是从客户端端点(Android 应用程序)收到此错误消息:
I am making use of this cool thing Spring offers: Spring RESTWebService (Version of spring is 3). If I access the URL from browser I can see the JSON response, but from a Client endpoint (Android application) iIreceive this error message:
Caused by: org.springframework.web.client.ResourceAccessException:
I/O error: Can not deserialize instance of MyObject out of START_ARRAY token
at [Source: org.apache.http.conn.EofSensorInputStream@4076e940; line: 1,
column: 1]; nested exception is org.codehaus.jackson.map.JsonMappingException:
Can not deserialize instance of MyObject out of START_ARRAY token
at [Source: org.apache.http.conn.EofSensorInputStream@4076e940; line: 1, column: 1]
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:466)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:414)
at org.springframework.web.client.RestTemplate.getForEntity(RestTemplate.java:234)
at com.be.android.locateconsultants.resources.AsyncTaskRESTServiceCaller.doInBackground(AsyncTaskRESTServiceCaller.java:43)
at com.be.android.locateconsultants.resources.AsyncTaskRESTServiceCaller.doInBackground(AsyncTaskRESTServiceCaller.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:252)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
... 4 more
Caused by: org.codehaus.jackson.map.JsonMappingException: Can not deserialize
instance of MyObject out of START_ARRAY token
at [Source: org.apache.http.conn.EofSensorInputStream@4076e940; line: 1, column: 1]
at org.codehaus.jackson.map.deser.StdDeserializationContext.mappingException(StdDeserializationContext.java:198)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeUsingCreator(BeanDeserializer.java:565)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:365)
at org.codehaus.jackson.map.ObjectMapper._readMapAndClose(ObjectMapper.java:2395)
at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1655)
at org.springframework.http.converter.json.MappingJacksonHttpMessageConverter.readInternal(MappingJacksonHttpMessageConverter.java:135)
at org.springframework.http.converter.AbstractHttpMessageConverter.read(AbstractHttpMessageConverter.java:154)
at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:74)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:632)
at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:618)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:459)
... 10 more
MyObject 结构与服务器端应用的结构相同.
MyObject structure is the same as the one from the server side application.
我尝试像这样请求服务器:
I have tried to request the server like this:
final String url = ".....";
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<Consultant> responseEntity = restTemplate.getForEntity(
url, Consultant.class);
或者像这样:
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<String> entity = new HttpEntity<String>(headers);
ResponseEntity<MyObject> response = restTemplate
.exchange("....",HttpMethod.GET, entity, MyObject.class);
System.out.println("RESPONSE: " + response.getBody());
但是还是和上面一样的错误.目前无法弄清楚我缺少什么,任何想法或提示都会很棒.谢谢.
But still the same error as above.Can't figure out what I am missing at this point, any idea or hints would be great.Thank you.
推荐答案
类似情况的解决方案是映射到Consultant[].class
如果您尝试反序列化映射对象的 JSON 数组,则这适用.
Solution in a similar situation was to map to Consultant[].class
This applies if you try to deserialize a JSON array of your mapped objects.
这篇关于无法从 Spring 3 REST Web 服务中的 START_ARRAY 令牌反序列化对象实例的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!