Python:ipaddress.AddressValueError:至少应包含3个部分

问题描述

ipaddress.IPv4Network属性可用于检查是否保留了任何IP地址.

An attribute of ipaddress.IPv4Network can be used to check if any IP address is reserved.

在IPython中:

In [52]: IPv4Address(u'169.254.255.1').is_private
Out[52]: False

但是，如果我在函数中尝试完全相同的事情:

Yet if I try the exact same thing in a function:

import ipaddress
def isPrivateIp(ip):
    unicoded = unicode(ip)
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
        return True
    else:
        return False

print isPrivateIp(r'169.254.255.1')

我得到:

  File "isPrivateIP.py", line 13, in <module>
    print isPrivateIp(ur'169.254.255.1')
  File "isPrivateIP.py", line 7, in isPrivateIp
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 2119, in __init__
    self.network_address = IPv6Address(self._ip_int_from_string(addr[0]))
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 1584, in _ip_int_from_string
    raise AddressValueError(msg)
ipaddress.AddressValueError: At least 3 parts expected in u'169.254.255.1'

为什么会这样?

注意:在python 2中，IP地址必须作为unicode对象传递给ipaddress函数，因此在字符串输入ip上调用unicode().

Note: In python 2, ip addresses must be passed to ipaddress functions as unicode objects, hence calling unicode() on the string input ip.

推荐答案

ipaddress.IPv6Network()的预期输入与ipaddress.IPv4Network()不同.如果您从代码中删除or ipaddress.IPv6Network(unicoded).is_private，则可以正常工作.您可以从此处阅读更多信息.

The expected input for ipaddress.IPv6Network() is different than ipaddress.IPv4Network(). If you remove or ipaddress.IPv6Network(unicoded).is_private from your code it works fine. You can read more from here.

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