本文介绍了如何从 nodejs 子进程(在 windows 和 linuxish 中)获取 cwd(当前工作目录)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试通过 nodejs 运行一个脚本:
I'm trying to run a script via nodejs that does:
cd ..
doSomethingThere[]
但是,要做到这一点,我需要执行多个子进程并在这些进程之间传递环境状态.我想做的是:
However, to do this, I need to executed multiple child processes and carry over the environment state between those processes. What i'd like to do is:
var exec = require('child_process').exec;
var child1 = exec('cd ..', function (error, stdout, stderr) {
var child2 = exec('cd ..', child1.environment, function (error, stdout, stderr) {
});
});
或者至少:
var exec = require('child_process').exec;
var child1 = exec('cd ..', function (error, stdout, stderr) {
var child2 = exec('cd ..', {cwd: child1.process.cwd()}, function (error, stdout, stderr) {
});
});
我该怎么做?
推荐答案
以父目录为 cwd 启动子项:
to start child with parent dir as cwd:
var exec = require('child_process').exec;
var path = require('path')
var parentDir = path.resolve(process.cwd(), '..');
exec('doSomethingThere', {cwd: parentDir}, function (error, stdout, stderr) {
// if you also want to change current process working directory:
process.chdir(parentDir);
});
更新:如果您想检索孩子的 cwd:
Update: if you want to retrieve child's cwd:
var fs = require('fs');
var os = require('os');
var exec = require('child_process').exec;
function getCWD(pid, callback) {
switch (os.type()) {
case 'Linux':
fs.readlink('/proc/' + pid + '/cwd', callback); break;
case 'Darwin':
exec('lsof -a -d cwd -p ' + pid + ' | tail -1 | awk \'{print $9}\'', callback);
break;
default:
callback('unsupported OS');
}
}
// start your child process
// note that you can't do like this, as you launch shell process
// and shell's child don't change it's cwd:
// var child1 = exec('cd .. & sleep 1 && cd .. sleep 1');
var child1 = exec('some process that changes cwd using chdir syscall');
// watch it changing cwd:
var i = setInterval(getCWD.bind(null, child1.pid, console.log), 100);
child1.on('exit', clearInterval.bind(null, i));
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