问题描述
我有一个 PowerShell 脚本，它使用脚本的当前目录执行一些操作.因此，当在该目录中时，运行 .\script.ps1 可以正常工作.
I have a PowerShell script that does some stuff using the script’s current directory. So when inside that directory, running .\script.ps1 works correctly.
现在我想从不同的目录调用该脚本而不更改脚本的引用目录.所以我想调用 ..\..\dir\script.ps1 并且仍然希望该脚本按照从其目录内部调用的方式运行.
Now I want to call that script from a different directory without changing the referencing directory of the script. So I want to call ..\..\dir\script.ps1 and still want that script to behave as it was called from inside its directory.
我该怎么做，或者我如何修改脚本以使其可以从任何目录运行?
How do I do that, or how do I modify a script so it can run from any directory?
推荐答案
您的意思是您想要脚本自己的路径，以便您可以引用脚本旁边的文件?试试这个:
Do you mean you want the script's own path so you can reference a file next to the script? Try this:
$scriptpath = $MyInvocation.MyCommand.Path
$dir = Split-Path $scriptpath
Write-host "My directory is $dir"
您可以从 $MyInvocation 及其属性中获取大量信息.
You can get a lot of info from $MyInvocation and its properties.
如果要引用当前工作目录中的文件，可以使用 Resolve-Path 或 Get-ChildItem:
If you want to reference a file in the current working directory, you can use Resolve-Path or Get-ChildItem:
$filepath = Resolve-Path "somefile.txt"
编辑(基于 OP 的评论):
EDIT (based on comment from OP):
# temporarily change to the correct folder
Push-Location $dir
# do stuff, call ant, etc
# now back to previous directory
Pop-Location
可能还有其他使用 Invoke-Command 实现类似功能的方法.
There's probably other ways of achieving something similar using Invoke-Command as well.
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