本文介绍了如何在java中构建url?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用StringBuilder构建一个String
I am building a String with StringBuilder
StringBuilder builder = new StringBuilder();
builder.append("my parameters");
builder.append("other parameters");
然后我建立一个网址
Url url = new Url(builder.toString());
然后我尝试连接
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
但是网址似乎与我得到的结果不对。这就像某些参数被错误传递。这就是为什么我认为问题出在StringBuilder的一部分。
But the url seems not to be right from the results i get. It's like some parameter is being false passed. That's why i think the problem is in the part of the StringBuilder.
问题在于我试图传递的双参数。
The problem is in a double parameter i try to pass.
double longitude = 23.433114;
String lng = String.ValueOf(longitude);
然后我把它放在网址中。
但是如果我把它作为字符串给出结果是正确的。
And then i put it in the url.But if i give it as a string the result is correct.
String lng = "23.433114"
是否需要UrlEncoding?我将尝试下面建议的内容。
Is UrlEncoding necessary? I will try what is suggested below.
推荐答案
尝试apache的 URIBuilder
: [文档]
Try apache's URIBuilder
: [Documentation]
import org.apache.http.client.utils.URIBuilder;
// ...
URIBuilder b = new URIBuilder("http://example.com");
b.addParameter("t", "search");
b.addParameter("q", "apples");
Url url = b.build().toUrl();
Maven依赖:
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.1</version>
</dependency>
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