如何在类中创建模板函数？ （C ++）

问题描述

我知道可以创建一个模板函数：

I know it's possible to make a template function:

template<typename T>
void DoSomeThing(T x){}

，可以创建一个模板类：

and it's possible to make a template class:

template<typename T>
class Object
{
public:
    int x;
};

但是可以使一个类不在模板中，然后在该类中创建一个函数模板？ Ie：

but is it possible to make a class not within a template, and then make a function in that class a template? Ie:

//I have no idea if this is right, this is just how I think it would look
class Object
{
public:
    template<class T>
    void DoX(){}
};

或某种程度，类不是模板的一部分，但函数是？

or something to the extent, where the class is not part of a template, but the function is?

推荐答案

您的猜测是正确的。你唯一要记住的是成员函数模板定义（除了声明）应该在头文件中，而不是cpp，虽然它不 必须在类声明本身的正文中。

Your guess is the correct one. The only thing you have to remember is that the member function template definition (in addition to the declaration) should be in the header file, not the cpp, though it does not have to be in the body of the class declaration itself.

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