GCC问题：使用依赖于模板参数的基类的成员

问题描述

以下代码不能用gcc编译，但是用Visual Studio编译：

The following code doesn't compile with gcc, but does with Visual Studio:

template <typename T> class A {
public:
    T foo;
};

template <typename T> class B: public A <T> {
public:
    void bar() { cout << foo << endl; }
};

我得到错误：

test.cpp: In member function ‘void B<T>::bar()’:
test.cpp:11: error: ‘foo’ was not declared in this scope

但它应该是！如果我将 bar 更改为

But it should be! If I change bar to

void bar() { cout << this->foo << endl; }

然后它会编译，但我不认为我有去做这个。

then it does compile, but I don't think I have to do this. Is there something in the official specs of C++ that gcc is following here, or is it just a quirk?

推荐答案

这改变了在C ++的官方规范中gcc是在这里，还是只是一个怪癖？ 。 C ++解析器在该版本中更加严格，根据规范，但仍然对有遗留或多平台代码库的人来说很恼人。

This changed in gcc-3.4. The C++ parser got much more strict in that release -- per the spec but still kinda annoying for people with legacy or multi-platform code bases.

这篇关于GCC问题：使用依赖于模板参数的基类的成员的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！