创建在C简单的计算器

问题描述

我试图写一个简单的C计算器脚本，只使用基本的+， - ，/，*。我有以下，但我不知道为什么它不能正常打印。

 ＃包括LT＆;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;INT主要（无效）
{    //介绍瓦尔
    双数字1，数字，结果;
    字符符号; //操作*， - ，+ /    //允许用户交互
    的printf（请输入您的公式\\ n）;
    scanf函数（％F％C％F，＆安培;数字1，和放大器;符号，＆安培;数字2）;    开关（符号）{
        案例'+'：
            结果=数字1 +数字2;
            打破;
        默认：
            的printf（别的事我不知道）;
            打破;
    }    的getchar（）;
    返回0;
}
 

为什么结果不被打印？我在这里做得不对，

 结果=数字1 +数字2;
 

解决方案

You calculate the answer properly, but do not print it anywhere.

You need to have something like:

printf("Answer: %f + %f = %f\n", number1, number2, result);

Without a print statement, nothing gets printed.

---

EDIT Responding to comment:

Did you do the printf after you calculate the result?Personally, I would put the printf just before the getchar();

For more debugging, just after your scanf, I would write:

printf("Input as received: number1 is %f\n number2 is %f\nsymbol is %c\n", number1, number2, symbol);

If that does not show the input that you typed, then something is wrong with how you gather input.

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