在laravel 5.1中以高效的方式吸引关注者

问题描述

我已经使用Eloquent for API构建了一个关注者系统(感谢)，但是查询(n+1)的速度非常慢，它需要5秒钟的响应时间，是我的操作方式.

I have build a follower system using Eloquent for API (thanks to John Bupit ) but I am getting very slow query (n+1), its taking 5 second for response, here is the way I have done it.

我需要知道当前帖子之后的当前用户，所以我在所有帖子后都添加了所有用户的id(这使得很多sql查询).

I need to know is current user following current post, so I have appended the id of all users following on every post (which is making a lot of sql queries).

发布模型

/**
 * The accessors to append to the model's array form.
 *
 * @var array
 */
protected $appends = ['followers'];

/**
 * Get the list of followers of this post.
 *
 * @return bool
 */
public function getFollowersAttribute()
{
    return $this->followers()->get()->lists('id');
}

如您所见，我在模型上添加了一个属性followers，该属性用于获取ids用户关注的列表.

As you can see I have added an attribute followers on model which fetches the lists of ids user following.

还有什么其他方法可以让用户获得以下发布状态，如何使其更快.

Is there any other way I can get the following state of post for user, How can I make it faster.

如果用户关注该帖子且关注者总数，我想显示关注.

I want to show Following if user is following the post with a count of total followers.

我从api返回每页20个帖子的分页列表，作为json.

I am returning a paginated list of 20 posts per page from API as json.

更新

我现在尝试过快速加载并快速加载，但是如何仅获取用户ID列表，而不获取漏洞用户模型.这是我的代码

I have tried eager loading and its fast now, but how can I get only the list of user ids, not hole user model. here is my code

$post->with([
  'followers' => function($q) {
      $q->select('user_id'); // select id is giving Column 'id' in field list is ambiguous
},

及其给了我

followers: [
{
    user_id: 32
},
{
    user_id: 3
},
{
    user_id: 21
},
{
    user_id: 33
},
{
    user_id: 46
},
{
    user_id: 30
}

]

我想要

followers : [45,2,45,87,12] //as array of ids

这会引起问题，例如，如果某个帖子获得1000个关注者，我敢打赌它会再次变慢，并且我不能限制eager loaded结果

it will cause problem, for example if a post get 1000 follower, I bet it will be slow again, and I cant limit the eager loaded result

$q->select('user_id')->limit(20); // Limit doesn't work

其他选项

另一种方法是在followers_count之类的帖子表上缓存关注者的数量，然后我可以使用某种方式检查登录用户是否使用标志ex跟踪每个帖子. is_following.我不知道我在这里迷路了.

One another way will be to cache number of followers on posts table like followers_countand then some way I can check that logged in user is following the each post using a flag ex. is_following. I dont know I am lost here.

请帮助大家，twitter，facebook是如何做到的?以便将关注者发布到帖子上，并且当前用户正在关注给定帖子.

推荐答案

您可以使用后，出现nofollow> array_reduce .

示例:

$followers = array_reduce($post->followers, function ($c, $i) {
    $c[] = $i->user_id;
}, []);

现在$followers包含所有关注者id.

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