问题描述
使用python2 zipfile.ZipFile
I got BadZipfile: Bad magic number for file header error while extracting a .zip using python2 zipfile.ZipFile
使用.zip解压缩时使用相同的.zip会给出file #1: bad zipfile offset (local header sig): 0，但是会使用退出代码2进行提取.
Same .zip when extracted with unzip gives file #1: bad zipfile offset (local header sig): 0 but gets extracted with exit code 2.
使用jar -xf file.zip时，该命令以$? == 0结束，未提取任何内容.
When using jar -xf file.zip the command completes with $? == 0 with nothing being extracted.
使用文件即可:
file -i file.zip
file.zip application/octet-stream; charset=binary
这为zipfile提供了错误的标题
This gives incorrect header for zipfile
$ hexdump -C file.zip | head -10
00000000 50 67 f0 de 1e 7a 29 e4 93 56 3f 11 a2 5f b6 97 |Pg...z)..V?.._..|
正确的标题是:
00000000 50 4b 03 04 14 00 08 08 08 00 28 3e 4b 4b 00 00 |PK........(>KK..|
为什么文件被列为application/octet-stream?
Why is the file listed as application/octet-stream ?
我在
Distributor ID: Ubuntu
Description: Ubuntu 14.04.5 LTS
Release: 14.04
Codename: trusty
怎么回事?这是什么文件格式?有指针吗?
Whats going on ? What file format is this ? Any pointers ?
推荐答案
您尝试过吗?
import zipfile
zip_ref = zipfile.ZipFile(path_to_zip_file, 'r')
zip_ref.extractall(directory_to_extract_to)
zip_ref.close()
这篇关于在python中提取.zip的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！