问题描述
我已经创建了10个线程，并希望在一个循环的方式执行3次。最初，所有
线程正在等待。主线程发送信号给线程0，在接收信号的线程0醒了，
然后执行一些任务，然后将信号发送到线程1和重复类似thread1-> thread2-> thread3
....-> thread9。那么线程9->线程0。
我想实现这个
主题我，做一些任务，然后将信号发送到线程（我+ 1），然后拧我去睡觉。螺纹（I + 1）将在t秒后醒来（指线程i + 1的唤醒时间 - 线程我睡眠时间= T秒）螺纹（I + 1）会做一些任务，将信号发送到线程（我+ 2）和去睡眠，这将重复数（3）倍。
虽然我能够从线程0->线程发送信号1 - > ....螺纹9（循环只执行一次），我无法发送信号线9 - >线程0 和这就是为什么我不能够重复这个循环 3次。
我在哪里犯错？
任何帮助将是非常美联社preciated。
我使用的G ++ 4.6.3下的Linux内核2.6.32。
这是我期望的输出
创建5个线程
线程创建= 0
线程创建= 1
线程创建= 2
线程创建= 3
线程创建= 4
螺纹4受阻
螺纹盖帽3
线程2阻塞
线程1被阻止
线程0受阻
唤醒所有等待的线程...
线程0畅通
线程1畅通
线程2畅通
线程3畅通
主题4畅通 螺纹4阻塞//相同序列的repeataion
螺纹盖帽3
线程2阻塞
线程1被阻止
线程0受阻
线程0畅通
线程1畅通
线程2畅通
线程3畅通
主题4畅通
等待线程和清理
主体完工
下面是我的实际输出
创建5个线程
线程创建= 0
线程创建= 1
线程创建= 2
线程创建= 3
线程创建= 4
螺纹4受阻
螺纹盖帽3
线程2阻塞
线程1被阻止
线程0受阻
唤醒所有等待的线程...
线程0畅通
线程1畅通
线程2畅通
线程3畅通
主题4畅通
等待线程和清理
主体完工
下面是我的code
的#include＆LT; pthreads.h中＆GT;
＃包括LT＆;＆iostream的GT;
＃包括LT＆;＆stdio.h中GT;
/ *为了安全条件变量使用，必须使用一个布尔值predicate和* /
/ *与条件的互斥。 * /
INT conditionMet = 0;
pthread_cond_t的COND [5];pthread_mutex_t互斥= PTHREAD_MUTEX_INITIALIZER;＃定义来确定nthreads 5无效*的ThreadFunc（无效* PARM）
{ INT I;
长期添加my_id =（长）PARM;
INT RC;//最初，所有的线程将等待
RC的pthread_mutex_lock =（安培;互斥）;
的printf（线程％d个阻塞\\ n，添加my_id）;
RC =调用pthread_cond_wait（安培; COND [添加my_id]＆安培;互斥）;
的printf（线程％d个畅通\\ n，添加my_id）;
RC =调用pthread_mutex_unlock（安培;互斥）;诠释计数= 0;而（计数++ 3;）//此行是没有意义的，因为没有预期repeatation。
{ RC的pthread_mutex_lock =（安培;互斥）; 而（！conditionMet）{
的printf（线程％d个阻塞\\ n，添加my_id）;
RC =调用pthread_cond_wait（安培; COND [添加my_id]＆安培;互斥）;
的printf（线程％d个畅通\\ n，添加my_id）;
} RC =调用pthread_mutex_unlock（安培;互斥）; //发送信号给下一个线程I + 1
RC的pthread_mutex_lock =（安培;互斥）;
RC =调用pthread_cond_signal（安培; COND [（添加my_id + 1）％来确定nthreads]）;
RC =调用pthread_mutex_unlock（安培;互斥）; }
返回NULL;
} INT主（INT ARGC，字符** argv的）
{
INT RC = 0;
INT I;
的pthread_t主题ID [确定nthreads] 对于（RC = 0;＆RC LT;确定nthreads; RC ++）
COND [RC] = PTHREAD_COND_INITIALIZER; 的printf（请输入测试用例 - ％S \\ N的argv [0]）; 的printf（创建％d个线程的\\ n，确定nthreads）;
对于（i = 0; I＆LT;确定nthreads ++我）{
RC = pthread_create的（安培;主题ID [Ⅰ]，NULL的ThreadFunc，（无效*）ⅰ）;
的printf（线程创建=％d个\\ N，I）;
} 睡眠（5）; / *睡不序列化线程一个非常可靠的方法* /
RC的pthread_mutex_lock =（安培;互斥）; / *条件已发生。设置该标志并唤醒等待的线程* /
conditionMet = 1;
的printf（醒醒所有等待的线程... \\ n）;
RC =调用pthread_cond_signal（放大器; COND [0]）;
RC =调用pthread_mutex_unlock（安培;互斥）; 的printf（等待线程和清理\\ n）;
对于（i = 0; I＆LT;确定nthreads ++我）{
RC =在pthread_join（主题ID [I]，NULL）;
}
pthread_cond_destroy（安培; COND [0]）;
pthread_mutex_destroy（安培;互斥）; 的printf（主完成\\ n）;
返回0;
}
指我自己解决我的问题。
中的所有线程循环赛序列运行一次，然后该程序终止/完整的执行为否线程都在等待下一回合后，全部完成。
所以要运行相同的多个序列（3）次，等变量需要正确地修改，以便每个线程将等待下一回合，直到3执行。
下面是修改后的程序：
无效*的ThreadFunc（无效* PARM）
{ INT I;
长期添加my_id =（长）PARM;
INT RC; / *
删除这部分，否则无输出，AGAIN绞死单个序列。
它不会进入里面循环while（计数++ 3;） //最初，所有的线程将等待
RC的pthread_mutex_lock =（安培;互斥）;
的printf（线程％d个阻塞\\ n，添加my_id）;
RC =调用pthread_cond_wait（安培; COND [添加my_id]＆安培;互斥）;
的printf（线程％d个畅通\\ n，添加my_id）;
RC =调用pthread_mutex_unlock（安培;互斥）;
* /
诠释计数= 0;而（计数++ 3;）
{ RC的pthread_mutex_lock =（安培;互斥）;
而（conditionMet！=添加my_id）
{
的printf（线程％d个阻塞\\ n，添加my_id）;
RC =调用pthread_cond_wait（安培; COND [添加my_id]＆安培;互斥）;
的printf（线程％d个畅通\\ n，添加my_id）;
} RC =调用pthread_mutex_unlock（安培;互斥）;
RC的pthread_mutex_lock =（安培;互斥）;
conditionMet =（添加my_id + 1）％来确定nthreads; //这是重要的，以等待下一次
RC =调用pthread_cond_signal（安培; COND [（添加my_id + 1）％来确定nthreads]）;
RC =调用pthread_mutex_unlock（安培;互斥）;
}
返回NULL;
}
I have created 10 threads and want to execute in a round robin fashion for 3 times. Initially allthreads are waiting. Main threads sends signal to thread 0, on receiving signal thread 0 woke up andthen perform some task and then send signal to thread 1 and this repeats like thread1-> thread2->thread3....->thread9. then thread 9-> thread 0.
I am trying to implement this
thread i, does some task, then send signal to thread (i+1) and then thread i goes for sleep. thread (i+1) will wake up after t sec (means thread i+1 wakeup time - thread i sleep time = t sec ), thread (i+1) will do some task, send signal to thread (i+2) and go for sleep and this will repeat for few(3) times.
Although I am able to send signal from thread 0-> thread 1 -> .... thread 9 (loop executed only once ), I am not able to send signal thread 9 -> thread 0 and that's why I am not able to repeat this loop for 3 times.
where I am making mistakes ?
Any help will be highly appreciated .I am using g++ 4.6.3 under linux kernel 2.6.32.
Here is my expected output
Create 5 threads
Thread created=0
Thread created=1
Thread created=2
Thread created=3
Thread created=4
Thread 4 blocked
Thread 3 blocked
Thread 2 blocked
Thread 1 blocked
Thread 0 blocked
Wake up all waiting threads...
Thread 0 unblocked
Thread 1 unblocked
Thread 2 unblocked
Thread 3 unblocked
Thread 4 unblocked
Thread 4 blocked // repeataion of same sequence
Thread 3 blocked
Thread 2 blocked
Thread 1 blocked
Thread 0 blocked
Thread 0 unblocked
Thread 1 unblocked
Thread 2 unblocked
Thread 3 unblocked
Thread 4 unblocked
Wait for threads and cleanup
Main completed
Here is my actual output
Create 5 threads
Thread created=0
Thread created=1
Thread created=2
Thread created=3
Thread created=4
Thread 4 blocked
Thread 3 blocked
Thread 2 blocked
Thread 1 blocked
Thread 0 blocked
Wake up all waiting threads...
Thread 0 unblocked
Thread 1 unblocked
Thread 2 unblocked
Thread 3 unblocked
Thread 4 unblocked
Wait for threads and cleanup
Main completed
Here is my code
#include <pthread.h>
#include <iostream>
#include <stdio.h>
/* For safe condition variable usage, must use a boolean predicate and */
/* a mutex with the condition. */
int conditionMet = 0;
pthread_cond_t cond[5];
pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
#define NTHREADS 5
void *threadfunc(void *parm)
{
int i;
long my_id = (long)parm;
int rc;
// Initially all threads will wait
rc = pthread_mutex_lock(&mutex);
printf("Thread %d blocked\n",my_id);
rc = pthread_cond_wait(&cond[my_id], &mutex);
printf("Thread %d unblocked\n", my_id);
rc = pthread_mutex_unlock(&mutex);
int count=0;
while(count++<3) // This line makes no sense, no repeatation as expected.
{
rc = pthread_mutex_lock(&mutex);
while (!conditionMet) {
printf("Thread %d blocked\n",my_id);
rc = pthread_cond_wait(&cond[my_id], &mutex);
printf("Thread %d unblocked\n", my_id);
}
rc = pthread_mutex_unlock(&mutex);
// sending signal to next thread i+1
rc = pthread_mutex_lock(&mutex);
rc = pthread_cond_signal(&cond[(my_id+1)%NTHREADS]);
rc = pthread_mutex_unlock(&mutex);
}
return NULL;
}
int main(int argc, char **argv)
{
int rc=0;
int i;
pthread_t threadid[NTHREADS];
for(rc=0;rc<NTHREADS;rc++)
cond[rc]= PTHREAD_COND_INITIALIZER;
printf("Enter Testcase - %s\n", argv[0]);
printf("Create %d threads\n", NTHREADS);
for(i=0; i<NTHREADS; ++i) {
rc = pthread_create(&threadid[i], NULL, threadfunc, (void *)i);
printf("Thread created=%d\n", i);
}
sleep(5); /* Sleep is not a very robust way to serialize threads */
rc = pthread_mutex_lock(&mutex);
/* The condition has occured. Set the flag and wake up any waiting threads */
conditionMet = 1;
printf("Wake up all waiting threads...\n");
rc = pthread_cond_signal(&cond[0]);
rc = pthread_mutex_unlock(&mutex);
printf("Wait for threads and cleanup\n");
for (i=0; i<NTHREADS; ++i) {
rc = pthread_join(threadid[i], NULL);
}
pthread_cond_destroy(&cond[0]);
pthread_mutex_destroy(&mutex);
printf("Main completed\n");
return 0;
}
After referring to pthread_wait I myself solved my problem.
All the threads runs in a round robin sequence for once, then the program terminate/complete execution as NO threads are WAITING for next turn, all finished .
So to run the same sequence multiple (3) times, wait variable needs to modified correctly so that each thread will wait for next turn until 3 execution.
Here is modified program :
void *threadfunc(void *parm)
{
int i;
long my_id = (long)parm;
int rc;
/*
DELETE THIS PORTION, OTHERWISE NO OUTPUT, AGAIN HANGED BEFORE SINGLE SEQUENCE.
IT WILL NOT ENTER INSIDE LOOP while(count++<3)
// Initially all threads will wait
rc = pthread_mutex_lock(&mutex);
printf("Thread %d blocked\n",my_id);
rc = pthread_cond_wait(&cond[my_id], &mutex);
printf("Thread %d unblocked\n", my_id);
rc = pthread_mutex_unlock(&mutex);
*/
int count=0;
while(count++<3)
{
rc = pthread_mutex_lock(&mutex);
while ( conditionMet != my_id)
{
printf("Thread %d blocked\n",my_id);
rc = pthread_cond_wait(&cond[my_id], &mutex);
printf("Thread %d unblocked\n", my_id);
}
rc = pthread_mutex_unlock(&mutex);
rc = pthread_mutex_lock(&mutex);
conditionMet = (my_id+1)%NTHREADS ; // This is important to wait for next time
rc = pthread_cond_signal(&cond[(my_id+1)%NTHREADS]);
rc = pthread_mutex_unlock(&mutex);
}
return NULL;
}
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