问题描述
我需要一个Date.prototype.addBusDays函数
，它将一个整数作为添加到日期的工作天数。
I need a Date.prototype.addBusDays functionthat'll take an integer as the number of working days to add to the date.
然而，有两个考虑：1.周末，假期（假设我想像一个预设的数组来比较，如果开始日期和结束日期包含3个假期，那么你推出结束日期3）
However, there are two considerations: 1. Weekends, 2. Holidays (which I imagine would be a preset array to compare against. If beginning date and end date contain 3 holidays, then you push out the end date by 3)
我在网上遇到了一些脚本，我可以想到的一个困境就是让你说，首先处理所有的周末，然后你做假期，如果你+1了到假期），您的结束日期再次被推入一个周末...<
任何想法？
谢谢！
I have come across some scripts online, one dilemma I can think of is, lets say you address all the weekends first, then you do the holidays, what if you +1 day (due to holiday), and your end date is pushed into a weekends again...<
Any ideas?Thanks!
编辑：
这是我正在开发的调度工具的一部分，这意味着日期将与连接在一起的任务相关联。将1天添加到任务中，将触发重新计算与之相关的所有日期，可能是数据库中的所有日期。
This is a part of a scheduling tool I am developing, which mean the dates will be tied to tasks which are linked together. Adding 1 day to a task, will trigger a recalculation of everything tied to it, potentially all dates in the database.
推荐答案
会做一个循环。继续添加天数，直到您打了一天。
I would do a loop. Keep adding days until you hit a day that works.
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