Jax RS REST API-OAuth 2.0和控件来源

问题描述

我有一个使用Java JAX-RS构建的REST API，该API将会公开，并且受到OAuth 2.0的保护.

I have a REST API built using Java JAX-RS, the API will be exposed to public and it is protected by OAuth 2.0.

我计划从正在构建的内部项目中使用此API，并且因为它是我的API，所以我不希望用户授权我对此API进行调用.

I plan to use this API from internal projects I am building and because it is my API, I don't expect the user to authorise me to make calls to this API.

现在，我正在使用过滤器来检查访问令牌，并根据我的OAuth Provider(配置示例)对其进行验证:

Right now, I am using filters to check access token and validate it against my OAuth Provider, sample of configuration :

<!-- Exposing the facility service as a REST service -->
<jaxrs:server id="restContainer" address="/">
    <jaxrs:serviceBeans>
      .. services beans
    </jaxrs:serviceBeans>
    <jaxrs:providers>
      <ref bean="oauthFilter"/> <-- filter to validate oauth
      <ref bean="apiUsageFilter"/> <-- filter to check api usage (integrated with 3scale)
      <ref bean="jacksonProvider" />
      <ref bean="exceptionMapper" />
    </jaxrs:providers>
    <jaxrs:extensionMappings>
      <entry key="json" value="application/json" />
      <entry key="xml" value="application/xml" />
      <entry key="html" value="text/html" />
    </jaxrs:extensionMappings>
    <jaxrs:features>
      <bean class="org.apache.cxf.feature.LoggingFeature"/>
    </jaxrs:features>
</jaxrs:server>

我想知道是否可以实现一个新的过滤器来检查呼叫的起源，如果它是来自列出的ip/域中的，则绕过oauth，如果没有，则继续进行oauth.

I am wondering if I can implement a new filter to check origin of the call, if it is from among the listed ip(s)/domain(s) then bypass oauth, if not, then proceed with oauth.

这种方法可行吗?这是一个好习惯吗?优点和缺点?

Is that approach possible ? would it be a good practice? Pros and Cons?

谢谢！

推荐答案

解决方案很简单:我们为服务器到服务器应用程序实现了客户端授权授予，为移动应用程序实现了资源所有者凭证授权授予(没有后端)在OAuth 2.0服务器中.

The solution was simple : we implemented Client authorization grant for server-to-server applications, and Resource Owner Credentials authorization grant for mobile apps (that don't have backend) in the OAuth 2.0 server.

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