对列进行条件计数，并对结果进行平均计算

问题描述

我有一个具有这种结构的数据框

I have a dataframe with this structure

v1|v2|v3|
 2| 3| 4|
  | 5| 4|
 5| 1| 4|

我希望计算每列的所有4和5，然后将其除以该列所有条目的数目.之后，我想计算所有这些值的平均值.在这种情况下(1/2+1/3+3/3)/3=0.611

I waht to count all 4's and 5's for each column and divide it by the number of all entries of that column. Afterwards I want to calculate the mean of all these values. In this case (1/2+1/3+3/3)/3=0.611

sum over x(Count Vx if 4 or 5)/Count Vx(without missings)/x

到目前为止，我尝试过的是:df[df > 4 and df > 5].count()，但在这里我已经收到很多错误.有谁能走上正确的轨道?

What I have tried so far is:df[df > 4 and df > 5].count() but I already get a lot of errors here. Anyone who can bring on on the right track?

推荐答案

您可以尝试:

df.isin([4,5]).sum().div(df.count()).mean()

输出:

0.611111111111111

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