本文介绍了如何用dyanamically舍入小数值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
大家好,
我需要四舍五入值
Ex:2.365变为2.360
3.239变成3.230
谢谢
Afsal
Hi All ,,
I need to round a decimal value
Ex : 2.365 become 2.360
3.239 become 3.230
thanks
Afsal
推荐答案
double inVal = 2.365;
double outVal = Math.Truncate(inVal * 100) / 100;
string outStr = outVal.ToString("#.000");
2.360的十进制值是2.36
outVal - > 2.36
outStr - > 2.360
[Agent_Spock]
或你可以这样做
decimal value of 2.360 is 2.36
outVal ->2.36
outStr ->2.360
[Agent_Spock]
or you can do it like this
decimal value = Math.Round(Convert.ToDecimal("12.395"), 2);
string outStr = value.ToString("#.000");
价值是12.4
outStr是12.400
value is 12.4
outStr is 12.400
System.Math.Round(x,0)
double d = 1.275;
Math.Round(d, 2); // 1.27
Math.Round((decimal)d, 2); // 1.28
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