在PHP中实现Vincenty公式

问题描述

我一直在尝试通过以下方式实现 Vincenty的公式:

I've been attempting to implement Vincenty's formulae with the following:

    /* Implemented using Vincenty's formulae from http://en.wikipedia.org/wiki/Vincenty%27s_formulae,
 * answers "Direct Problem".
 * $latlng is a ('lat'=>x1, 'lng'=>y1) array
 * $distance is in miles
 * $angle is in degrees
 */
function addDistance($latlng, $distance, $bearing) {
    //variables
    $bearing = deg2rad($bearing);
    $iterations = 20; //avoid too-early termination while avoiding the non-convergant case

    //knowns
    $f = EARTH_SPHEROID_FLATTENING; //1/298.257223563
    $a = EARTH_RADIUS_EQUATOR_MILES; //3963.185 mi
    $phi1 = deg2rad($latlng['lat']);
    $l1 = deg2rad($latlng['lng']);
    $b = (1 - $f) * $a;

    //first block
    $tanU1 = (1-$f)*tan($phi1);
    $U1 = atan($tanU1);
    $sigma1 = atan($tanU1 / cos($bearing));
    $sinalpha = cos($U1)*sin($bearing);
    $cos2alpha = (1 - $sinalpha) * (1 + $sinalpha);
    $usquared = $cos2alpha * (($a*$a - $b*$b) / 2);
    $A = 1 + ($usquared)/16384 * (4096+$usquared*(-768+$usquared*(320 - 175*$usquared)));
    $B = ($usquared / 1024)*(256*$usquared*(-128 + $usquared * (74 - 47*$usquared)));

    //the loop - determining our value
    $sigma = $distance / ($b * $A);
    for($i = 0; $i < $iterations; ++$i) {
        $twosigmam = 2*$sigma1 + $sigma;
        $delta_sigma = $B * sin($sigma) * (cos($twosigmam)+(1/4)*$B*(cos(-1 + 2*cos(cos($twosigmam))) - (1/6)*$B*cos($twosigmam)*(-3+4*sin(sin($sigma)))*(-3+4*cos(cos($twosigmam)))));
        $sigma = $distance / ($b * $A) + $delta_sigma;
    }

    //second block
    $phi2 = atan((sin($U1)*cos($sigma)+cos($U1)*sin($sigma)*cos($bearing)) / ((1-$f) * sqrt(sin($sinalpha) + pow(sin($U1)*sin($sigma) - cos($U1)*cos($sigma)*cos($bearing), 2))));
    $lambda = atan((sin($sigma) * sin($bearing)) / (cos($U1)*cos($sigma) - sin($U1)*sin($sigma)*cos($bearing)));
    $C = ($f / 16)* $cos2alpha * (4+$f*(4-3*$cos2alpha));
    $L = $lambda - (1 - $C) * $f * $sinalpha * ($sigma + $C*sin($sigma)*(cos($twosigmam)+$C*cos($sigma)*(-1+2*cos(cos($twosigmam)))));
    $alpha2 = atan($sinalpha / (-sin($U1)*sin($sigma) + cos($U1)*cos($sigma)*cos($bearing)));

    //and return our results
    return array('lat' => rad2deg($phi2), 'lng' => rad2deg($lambda));
}

    var_dump(addDistance(array('lat' => 93.129, 'lng' => -43.221), 20, 135);

问题是结果不合理-我得到的最大经度和纬度方差保持距离为20.不是以球面上的椭圆距离为单位吗?我是在误解什么，还是我的实现存在缺陷?

The issue is that the results are not reasonable - I'm getting variances of up to 20 latitude and longitude keeping the distance at 20. Is it not in units of elliptical distance on the sphere? Am I misunderstanding something, or is my implementation flawed?

推荐答案

维基百科页面直接问题"部分:

• 您的u 表达式的分母中有2，应有b ;
• 您的A和B表达式对于是否需要对初始分数因子进行括号以正确地将a / b * c表示为(a/b) * c不一致-没有括号会发生什么是我不知道的php语法问题答案，但您应该更清楚；
• 您应该迭代直到sigma没有明显变化为止"，这可能会或可能不会发生在您固定的迭代次数中；
• 您的DELTA_sigma公式中有错误:
  • 在Wikipedia页面上，方括号[中的第一项是cos sigma (-1等，而您有cos (-1等，这是非常不同的；
  • 在相同的公式中以及以后，请注意， cos x 表示(cos x)(cos x)，不是 cos cos x！
  • Your u expression has 2 in the denominator where it should have b;
  • Your A and B expressions are inconsistent about whether the initial fraction factor needs to be parenthesised to correctly express a / b * c as (a/b) * c - what happens without parentheses is a php syntax issue which I don't know the answer to, but you should favour clarity;
  • You should be iterating "until there is no significant change in sigma", which may or may not happen in your fixed number of iterations;
  • There are errors in your DELTA_sigma formula:
    • on the wikipedia page, the first term inside the square bracket [ is cos sigma (-1 etc, whereas you have cos (-1 etc, which is very different;
    • in the same formula and also later, note that cos x means (cos x)(cos x), not cos cos x!

    我认为就这些.

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