问题描述
我是新的模板,所以也许这是一个琐碎的事情,但我不能得到它的工作。我试图得到一个类成员函数的部分专门化。最短的代码是:
template< typename T,int nValue> class Object {
private:
T m_t;
Object();
public:
Object(T t):m_t(t){}
T Get(){return m_t; }
Object& Deform(){
m_t * = nValue;
return * this;
}
};
template< typename T>
Object< T,0>& Object< T,0> :: Deform(){
this-> m_t = -1;
return * this;
}
int main(){
Object< int,7> nObj(1);
nObj.Deform();
std :: cout<< nObj.Get();
}
我尝试使用非成员函数,
但是,每当我尝试部分规范。的成员函数我得到的形式的错误:
PartialSpecification_MemberFu.cpp(17):错误:模板参数
列表必须匹配参数列表对象< T,0>& Object< T,0> :: Deform()。不喜欢任何帮助: - ) >解决方案你不能只部分专门化一个成员函数,你必须部分专业化整个类。因此,你需要像下面这样:
template< typename T&
class Object< T,0>
{
private:
T m_t;
Object();
public:
Object(T t):m_t(t){}
T Get(){return m_t; }
Object& Deform()
{
std :: cout< Spec\\\
;
m_t = -1;
return * this;
}
};
I'm new to templates so maybe this is a trivial thing but I cannot get it to work. I'm trying to get partial specialization of a class member function. The shortest code would be:
template <typename T, int nValue> class Object{
private:
T m_t;
Object();
public:
Object(T t): m_t(t) {}
T Get() { return m_t; }
Object& Deform(){
m_t*=nValue;
return *this;
}
};
template <typename T>
Object<T,0>& Object<T,0>::Deform(){
this->m_t = -1;
return *this;
}
int main(){
Object<int,7> nObj(1);
nObj.Deform();
std::cout<<nObj.Get();
}
I tried with nonmember functions and that's worked fine. What also works fine is full specialization of a member function.
But, whenever I try with partial spec. of a member function I get error of the form:
PartialSpecification_MemberFu.cpp(17): error: template argument
list must match the parameter list Object<T,0>& Object<T,0>::Deform().
Would appreciate any help :-)
解决方案 You cannot partially specialize only a single member function, you must partially specialize the whole class. Hence you'll need something like:
template <typename T>
class Object<T, 0>
{
private:
T m_t;
Object();
public:
Object(T t): m_t(t) {}
T Get() { return m_t; }
Object& Deform()
{
std::cout << "Spec\n";
m_t = -1;
return *this;
}
};
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