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问题描述

我有以下形式的作业&空检查以避免在我的地图中进行重复查找。

在Dart中是否有更好或更惯用的方式?

I have the following form of assignment & null checks to avoid double lookups in my maps.
Is there a better or more idiomatic way to do this in Dart?

bool isConnected(a, b){
  List list;
  return (
    ((list = outgoing[a]) != null && list.contains(b)) ||
    ((list = incoming[a]) != null && list.contains(b))
  );
}


推荐答案

知道的运算符可用于这种情况:

As of Dart 1.12 null-aware operators are available for this type of situation:

bool isConnected(a, b) {
  bool outConn = outgoing[a]?.contains(b) ?? false;
  bool inConn = incoming[a]?.contains(b) ?? false;
  return outConn || inConn;
}

?。如果左侧为null,则运算符会短路至null,如果 ?? 运算符返回左侧,则运算符会短路至右侧;

The ?. operator short-circuits to null if the left-hand side is null, and the ?? operator returns the left-hand side if it is not null, and the right-hand side otherwise.

语句

outgoing[a]?.contains(b)

因此将得出,如果去向[a] ,或者布尔结果为包含(b),如果不是。

will thus either evaluate to null if outgoing[a] is null, or the boolean result of contains(b) if it is not.

这意味着结果语句将是以下之一:

That means the resulting statement will be one of the following:

bool outConn = null ?? false; // false
bool outConn = false ?? false; // false
bool outConn = true ?? false; // true

>布尔值,这意味着 inConn outConn 均保证为非空,从而使我们可以返回 ||| 两者。

The same applies to the inConn boolean, which means both inConn and outConn are guaranteed to be non-null, allowing us to return the result of ||ing the two.

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08-20 03:01