成员函数作为回调

问题描述

我想将一个实例化对象的成员函数传递给另一个函数。示例代码如下。我对任何策略开放，包括调用功能（）从memberfuncpointertestclass使用类似lambda或std :: bind类似的函数。请注意，我不明白大多数线程我发现与谷歌关于lambda或std :: bind，所以请，如果可能，保持简单。还要注意，我的集群没有C + + 11，我想保持functional（）简单，因为它是。谢谢！

I would like to pass a member function of an instantiated object to another function. Example code is below. I am open for any strategy that works, including calling functional() from another function inside memberfuncpointertestclass using something like lambda or std::bind. Please note that I did not understand most of the threads I found with google about lambda or std::bind, so please, if possible, keep it simple. Also note that my cluster does not have C++ 11 and I would like to keep functional() as simple as it is. Thank you!

int functional( int (*testmem)(int arg) )
{
    int a = 4;
    int b = testmem(a);
    return b;
}

class memberfuncpointertestclass
{
public:
    int parm;
    int member( int arg )
    {
        return(arg + parm);
    }
};

void funcpointertest()
{
    memberfuncpointertestclass a;
    a.parm = 3;

    int (*testf)(int) = &a.member;

    std::cout << functional(testf);
}

int main()
{
    funcpointertest();
    return 0;
}

推荐答案

code> std :: function ，一个多态函数包装器。传递函数（...）这样的函数对象：

This is a job for std::function, a polymorphic function wrapper. Pass to functional(...) such a function object:

#include <functional>

typedef std::tr1::function<int(int)> CallbackFunction;

int functional(CallbackFunction testmem)
{
    int a = 4;
    int b = testmem(a);
    return b;
}

然后使用 std :: bind 创建一个类型相同的函数对象，它包装了实例a的memberfuncpointertestclass :: method（）：

then use std::bind to create a function object of the same type that wraps memberfuncpointertestclass::method() of instance a:

void funcpointertest()
{
    memberfuncpointertestclass a;
    a.parm = 3;

    CallbackFunction testf = std::bind(&memberfuncpointertestclass::member, &a, std::placeholders::_1);

    std::cout << functional(testf);
}

检查了解更多详情。

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