在swift类中实现AsyncSocket回调 | 在swift类中实现AsyncSocket回调

本文介绍了在swift类中实现AsyncSocket回调的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有一个自定义的ViewController委托类，它处理ui操作，例如在文本视图中单击按钮和显示文本。

I have a custom ViewController delegate class, which handles ui actions such as button clicked and display text in a text view.

现在我想在中使用AsyncSocket类。我已经能够创建一个套接字对象

Now I want to use AsyncSocket in the class. I have been able to create a socket object

var tcpSocket = GCDAsyncSocket(delegate: self, delegateQueue: dispatch_get_main_queue())

现在我想实现那些回调函数，例如didConnectToHosts（...），其声明在GCDAsyncSocket中提供.h：

Now I want to implement those callback functions, such as didConnectToHosts(...) whose declaration is provided in GCDAsyncSocket.h:

- (void)socket:(GCDAsyncSocket *)sock didConnectToHost:(NSString *)host port:(uint16_t)port;

如何在swift类中实现此功能？

How do I implement this function in my swift class?

推荐答案

// - (void)socket:(GCDAsyncSocket *)sock didConnectToHost:(NSString *)host port:(uint16_t)port;
func socket(socket : GCDAsyncSocket, didConnectToHost host:String, port p:UInt16)

// - (void)socket:(GCDAsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag;
func socket(socket : GCDAsyncSocket, didReadData data:NSData, withTag tag:Int32)

不要忘记让你的swift类继承自NSObject，否则GCDAsyncSocket将无法将其指定为委托。

Don't forget to make your swift class inherit from NSObject, otherwise the GCDAsyncSocket will fail to assign it as a delegate.

另外，不要将任何参数标记为 var ，如 var didReadData数据：NSData

Also, do not mark any parameters as var as in var didReadData data:NSData

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