如何为Windows Phone 8执行JSON和XML数据

问题描述

我有大量数据。如何使用Restsharp或HTTPWebRequest从JSON和XML获取数据。

I have bulk amount of data. How to get data from JSON and XML using Restsharp or HTTPWebRequest.

推荐答案

var client = new RestClient("your url");
               var request = new RestRequest("request url ", Method.POST);
               request.AddParameter("email", txtEmail.Text.ToString());
               request.AddParameter("password", txtPassword.Password.ToString());
              client.ExecuteAsync(request, response =>
                {
                    try
                    {
                        var IsSuccess = JsonConvert.DeserializeObject<loginobject>(response.Content);


                });
</loginobject>

var client = new RestClient("Web service url/");

           string url = string.Format("MobileApp/api/JobSeeker/Interview/SessionID/{0}/lng/{1}", sessionID,language);

           var request = new RestRequest(url, Method.GET);

           request.AddParameter("Authorization-Token", "ZJ6/3tldwf1gHj6uMUVSgQ==", ParameterType.HttpHeader);

           client.ExecuteAsync(request, response =>
           {
               InterviewResponse(response.Content);
           });

 private void InterviewResponse(string xmlString)
        {

            XDocument x = XDocument.Parse(xmlString);

            var collections = x.Root.Elements().ToList();

            List<interviews> listofJobs = new List<interviews>();

            foreach (var item in collections)
            {
                Interviews job = new Interviews();

                foreach (var el in item.Elements())
                {
                    switch (el.Name.LocalName)
                    {
                        case "EmployerName":
                            job.EmployerName = el.Value;
                            break;
                        case "InterviewType":
                            job.InterviewType = el.Value;
                            break;
                        case "JobCode":
                            job.JobCode = el.Value;
                            break;
                        case "JobTitle":
                            job.JobTitle = el.Value;
                            break;
                        case "Location":
                            job.Location = el.Value;
                            break;
                        case "Schedule":
                            job.Schedule = el.Value;
                            break;
                    }
                }

                listofJobs.Add(job);
            }

        }


</interviews></interviews>

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